[英]Extracting an array from another array in PHP
I have the following array (contents retrieved from a DB): 我有以下数组(从数据库检索的内容):
array (size=4)
0 =>
array (size=2)
'number' => string 'one' (length=3)
'name' => string 'Billy' (length=5)
1 =>
array (size=2)
'number' => string 'two' (length=3)
'name' => string 'Mariah' (length=6)
2 =>
array (size=2)
'number' => string 'three' (length=5)
'name' => string 'Cindy' (length=5)
3 =>
array (size=2)
'number' => string 'four' (length=4)
'name' => string 'Daniel' (length=6)
I need to create an array as follows: 我需要创建一个数组,如下所示:
$info = array('one' => 'Billy', 'two' => 'Mariah', 'three' => 'Cindy', 'four' => 'Daniel');
I used a foreach loop to construct the desired array: 我使用了foreach循环来构造所需的数组:
$info = array();
foreach ($result as $row) {
$info[] = array($row['number'] => $row['name']);
}
and a var_dump() gives me this instead: 而var_dump()却给了我这个:
array (size=4)
0 =>
array (size=1)
'one' => string 'Billy' (length=5)
1 =>
array (size=1)
'two' => string 'Mariah' (length=6)
2 =>
array (size=1)
'three' => string 'Cindy' (length=5)
3 =>
array (size=1)
'four' => string 'Daniel' (length=6)
How can I achieve the desired array in PHP? 如何在PHP中获得所需的数组? Thanks for your help in advance.
感谢您的帮助。
You were close. 你近了
$info = array();
foreach ($result as $row) {
$info[$row['number']] =$row['name'];
}
With PHP >= 5.5.0 it's much easier: 使用PHP> = 5.5.0会容易得多:
$info = array_column($result, 'name', 'number');
Or use the PHP Implementation of array_column() 或使用array_column()的PHP实现
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