如何使用javascript将json数据从一个html页面传递到另一html页面？

Question

I have to pass Json data which is generated after inserting the info into datbase table, Now I have to pass this info to other page BookingConformation.html . 我必须传递将信息插入datbase表后生成的Json数据，现在我必须将此信息传递给其他页面BookingConformation.html 。

For example we will get the form server Welcome Mr/Mrs Mittel Thanks for booking home services your booking id is 1. So please tell me how to pass info which is get form server in javascript now I have to pass this info to other page, please help me on this. 例如，我们将获得表格服务器Welcome Mr / Mittel先生/女士感谢您预订上门服务，您的预订ID为1。所以请告诉我如何通过javascript将表格服务器中的信息传递给我，我必须将此信息传递至其他页面，请帮助我。

script 脚本

<script>
    $(document).ready(function(){
        $("#register-form").validate({
            rules: {
                userName: "required",                           
                email: {
                    required: true,
                    email: true
                },                                              
                userContactNumber: "required"                       
            },
            messages: {
                userName: "Please enter your Name",
                userContactNumber: "Please enter your Mobile number",                           
                email: "Please enter a valid email address",                                           
            },
            submitHandler: function(form) {

                var uName = $('#userName').val();   
                var mailId = $('#email').val();                 
                var mobNum = $('#userContactNumber').val();

                $.ajax({                
                    url:"http://localhost/bookRoom/book.php",
                    type:"POST",
                    dataType:"json",
                    data:{type:"booking", Name:uName, Email:mailId,  Mob_Num:mobNum},                                   
                    ContentType:"application/json",
                    success: function(response){
                    //alert(JSON.stringify(response));
                    //alert("success");                     
                    alert(response);
                    var globalarray = [];
                    globalarray.push(response);
                    window.localStorage.setItem("globalarray", JSON.stringify(globalarray));
                    window.location.href = 'BookingConformation.html';
                },
                    error: function(err){                           
                        window.location.href = 'error.html';
                    }
                });
                return false; // block regular submit
            }
        });
    });
</script>

server code 服务器代码

    <?php
    header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
    mysql_connect("localhost","root","7128");
    mysql_select_db("service");

    if(isset($_POST['type']))
    {
        if($_POST['type']=="booking"){
            $name = $_POST ['Name'];    
            $mobile = $_POST ['Mob_Num'];
            $mail = $_POST ['Email'];               
            $query1 = "insert into customer(userName, userContactNumber, email) values('$name','$mobile','$mail')";
            $query2 = "insert into booking(cust_email, cust_mobile, cust_name) values('$mail','$mobile','$name')";          

            $result1=mysql_query($query1);          
            $result2=mysql_query($query2);
            $id=mysql_insert_id();
            $value = "Welcome Mr/Mrs ".$name."  Thanks for booking home services your booking id is =  ".$id;
            echo json_encode($value);
        }
    }
    else{
        echo "Invalid format";
    }
?>

BookingConformation.html BookingConformation.html

<!DOCTYPE html>
<html>
    <head>
        <script type="text/javascript">
            function myFunction() {
                 var globalarray = [];
                 var arrLinks =[];
                 arrLinks = JSON.parse(window.localStorage.getItem("globalarray"));
                 document.getElementById("booking").innerHTML = arrLinks;
             }
        </script>
    </head>
    <body>  
        <p id="booking" onclick="myFunction()">Click me to change my HTML content (innerHTML).</p>
    </bod

y> Y>

Answer 1

If this is your real server side code then...its completely insecure. 如果这是您真正的服务器端代码，则...完全不安全。 You should never pass variables posted by users directly into your queries. 您永远不应将用户发布的变量直接传递到查询中。

$query2 = "insert into booking(cust_email, cust_mobile, cust_name) values('$mail','$mobile','$name')";

At least escape the values using "mysql_real_escape_string", or use prepared statements. 至少使用“ mysql_real_escape_string”对值进行转义，或使用准备好的语句。 And...dont use mysql anymore, use mysqli, which is almost identical to what you are using, but not deprecated soon. 并且...不再使用mysql，请使用mysqli，它与您所使用的几乎相同，但不会很快被弃用。

Also, you are json encoding a string that doesnt need to be json encoded, its just a piece of text and not valid json code. 另外，您正在json编码一个不需要进行json编码的字符串，它只是一段文本，并且不是有效的json代码。 This may be why @SimarjeetSingh Panghlia answer doesnt work for you. 这就是为什么@SimarjeetSingh Panghlia答案对您不起作用的原因。

instead of json_encoding that value, encode a structured array. 而不是json_encoding该值，而是对结构化数组进行编码。

$response = array( "status" => true );

if(isset($_POST['type']))
    {
        if($_POST['type']=="booking"){
            $name = mysql_real_escape_string( $_POST ['Name'] ));    
            $mobile = mysql_real_escape_string($_POST ['Mob_Num']);
            $mail = mysql_real_escape_string($_POST ['Email']);               
            $query1 = "insert into customer(userName, userContactNumber, email) values('$name','$mobile','$mail')";
            $query2 = "insert into booking(cust_email, cust_mobile, cust_name) values('$mail','$mobile','$name')";          

            $result1 = mysql_query($query1);          
            $result2 = mysql_query($query2);
            $id = mysql_insert_id();

            $response["message"] = "Welcome Mr/Mrs ".$name."  Thanks for booking home services your booking id is =  ".$id;/* make sure you strip tags etc to prevent xss attack */

        }
    }
    else{
        $response["status"] = false;
        $response["message"] = "Invalid format";
    }

    echo json_encode($response);

    /* Note that you are making the query using ContentType:"application/json", */

which means you should respond using json regardless if query is successful or not. 这意味着无论查询是否成功，都应使用json进行响应。 I would also recommend using a simple jQuery plugin called jStorage, that allows easy get/set of objects without having to serialize them. 我还建议使用一个名为jStorage的简单jQuery插件，该插件可轻松获取/设置对象而无需序列化它们。

Answer 2

You can try this 你可以试试这个

declare variable on first page 在首页上声明变量

<script type="text/javascript">
    var globalarray = [];
    globalarray.push(response.d);
     window.localStorage.setItem("globalarray", JSON.stringify(globalarray));
</script>

Call that variable on second page 在第二页上调用该变量

<script type="text/javascript">
         var globalarray = [];
         var arrLinks =[];
         arrLinks = JSON.parse(window.localStorage.getItem("globalarray"));
        console.log(arrLinks);
</script>

Answer 3

You can use sessionStorage to store and retrieve JSON Data. 您可以使用sessionStorage来存储和检索JSON数据。

var complexdata = [1, 2, 3, 4, 5, 6];

// store array data to the session storage
sessionStorage.setItem("list_data_key",  JSON.stringify(complexdata));

//Use JSON to retrieve the stored data and convert it 
var storedData = sessionStorage.getItem("complexdata");
if (storedData) {
  complexdata = JSON.parse(storedData);
}

To remove sessionStorage Datas after using use sessionStorage.clear(); 要在使用后删除sessionStorage数据，请使用sessionStorage.clear();

如何使用javascript将json数据从一个html页面传递到另一html页面？

问题描述

3 个解决方案

解决方案1
1 2015-02-12 05:32:02

解决方案2
0 2015-02-12 04:51:50

解决方案3
0 2015-02-12 05:00:51

如何使用javascript将json数据从一个html页面传递到另一html页面？

问题描述

3 个解决方案

解决方案1 1 2015-02-12 05:32:02

解决方案2 0 2015-02-12 04:51:50

解决方案3 0 2015-02-12 05:00:51

解决方案1
1 2015-02-12 05:32:02

解决方案2
0 2015-02-12 04:51:50

解决方案3
0 2015-02-12 05:00:51