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在C中为字符串数组分配空间

[英]Mallocing Space for String Array in C

I need help malloc space for a string array and then returning this value as a pointer. 我需要帮助为字符串数组分配malloc空间,然后将此值作为指针返回。

How do I go about doing this? 我该怎么做呢? My code is: 我的代码是:

char * strArray[*arrLen] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));

I populate string array with memcpy and manual '\\0' adds. 我用memcpy和手动'\\ 0'添加字符串数组。 Then I return the value via: 然后,我通过以下方式返回值:

return (char **) strArray;

The error and warning I get upon compile are: 我在编译时遇到的错误和警告是:

answer03.c:48:3: error: variable-sized object may not be initialized
   char * strArray[*arrLen] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));
   ^
answer03.c:68:3: warning: function returns address of local variable [-Wreturn-local-addr]
   return (char **) strArray;
   ^
make: *** [all] Error 1

First, allocate memory for strArray . 首先,为strArray分配内存。

Assuming, arrLen is an integral variable, not a pointer, 假设arrLen是整数变量,而不是指针,

char** strArray = malloc(arrLen*sizeof(*strArray));
if ( strArray == NULL )
{
   // Deal with error condition
}

Then, allocate memory for each element of the array. 然后,为数组的每个元素分配内存。

for ( i = 0; i < arrLen; ++i )
{
   strArray[i] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));
   if ( strArray[i] == NULL )
   {
      // Deal with error condition
   }
}

Then, return the array. 然后,返回数组。

return strArray;

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