[英]Mallocing Space for String Array in C
I need help malloc space for a string array and then returning this value as a pointer. 我需要帮助为字符串数组分配malloc空间,然后将此值作为指针返回。
How do I go about doing this? 我该怎么做呢? My code is:
我的代码是:
char * strArray[*arrLen] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));
I populate string array with memcpy and manual '\\0' adds. 我用memcpy和手动'\\ 0'添加字符串数组。 Then I return the value via:
然后,我通过以下方式返回值:
return (char **) strArray;
The error and warning I get upon compile are: 我在编译时遇到的错误和警告是:
answer03.c:48:3: error: variable-sized object may not be initialized
char * strArray[*arrLen] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));
^
answer03.c:68:3: warning: function returns address of local variable [-Wreturn-local-addr]
return (char **) strArray;
^
make: *** [all] Error 1
First, allocate memory for strArray
. 首先,为
strArray
分配内存。
Assuming, arrLen
is an integral variable, not a pointer, 假设
arrLen
是整数变量,而不是指针,
char** strArray = malloc(arrLen*sizeof(*strArray));
if ( strArray == NULL )
{
// Deal with error condition
}
Then, allocate memory for each element of the array. 然后,为数组的每个元素分配内存。
for ( i = 0; i < arrLen; ++i )
{
strArray[i] = malloc(srcStrLen - numOfDelimsInStr + (numOfDelimsInStr + 1));
if ( strArray[i] == NULL )
{
// Deal with error condition
}
}
Then, return the array. 然后,返回数组。
return strArray;
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