[英]Insert foreign key value
I have two entities Project and Task. 我有两个实体Project和Task。 Task`s project_id value is mapped with project`s id.Every time creating a new task for a specific project, the project_id in the Task table should be set.
任务的project_id值与项目id一起映射。每次为特定项目创建新任务时,应设置Task表中的project_id。 Is there another way of doing this except using the hidden input field form?
除了使用隐藏的输入字段表单之外,还有其他方法吗?
createAction of TaskController TaskController的createAction
public function createAction(Request $request)
{
$entity = new Tasks();
$form = $this->createCreateForm($entity);
$form->handleRequest($request);
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
return $this->redirect($this->generateUrl('tasks_show', array('id' => $entity->getId())));
}
return $this->render('TestBundle:Tasks:new.html.twig', array(
'entity' => $entity,
'form' => $form->createView(),
));
}
是的,在处理表单的控制器操作中调用setProject($project)
方法
First you need to get project that you want to assign tasks to it. 首先,您需要获得要为其分配任务的项目。 For example you can send it via
Request $request
then use it to query for Project Object
then assign task to this object. 例如,您可以通过
Request $request
发送它,然后使用它查询Project Object
然后将任务分配给该对象。
public function createAction(Request $request)
{
$entity = new Tasks();
// doctrine entity manager
$em = this->getDoctrine()->getManager();
// get project_id from query string
$project_id = $request->get('project_id');
// query database for project object
$project = $em->getRepository("TestBundle:Project")->find($project_id);
// assign task to project object
$entity->setProject($project);
$form = $this->createCreateForm($entity);
$form->handleRequest($request);
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
return $this->redirect($this->generateUrl('tasks_show', array('id' => $entity->getId())));
}
return $this->render('TestBundle:Tasks:new.html.twig', array(
'entity' => $entity,
'form' => $form->createView(),
));
}
Also newAction()
is better place to do this. 同样,
newAction()
是执行此操作的更好的位置。
I hope this helps. 我希望这有帮助。
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