Python：-将字符串转换为列表

Question

I have a string like groups(1,12,23,12) and I want to convert it into a list like [1,12, 23, 12] .

I tried this code, but output is not as excepted.

str = 'groups(1,12,23,12)'
lst = [x for x in str]

Please let me know...!

Answer 1

You could use re.findall method.

And don't use str as variable name.

>>> import re
>>> s = 'groups(1,12,23,12)'
>>> re.findall(r'\d+', string)
['1', '12', '23', '12']
>>> [int(i) for i in re.findall(r'\d+', s)]
[1, 12, 23, 12]

Without regex,

>>> s = 'groups(1,12,23,12)'
>>> [int(i) for i in s.split('(')[1].split(')')[0].split(',')]
[1, 12, 23, 12]

Answer 2

For an approach without regex

>>> a = "groups(1,12,23,12)"
>>> a= a.replace('groups','')
>>> import ast
>>> list(ast.literal_eval(a))
[1, 12, 23, 12]

Ref:

• The ast module
• str.replace method

Answer 3

1. Use regular expression to find numbers from the input string.
2. Use map method to convert string to integer.

eg

>>> import re
>>> a = 'groups(1,12,23,12)'
>>> re.findall("\d+", a)
['1', '12', '23', '12']
>>> map(int, re.findall("\d+", a))
[1, 12, 23, 12]

Answer 4

string = "groups(1,12,23,12)".replace('groups(','').replace(')','')
outputList = [int(x) for x in string.split(',')]