使用fork / execvp在C中编写一个简单的shell

Question

I have to develop a simple shell in C using system calls fork()/execvp(). So far my code takes in a command, splits it up using strtok into an array argv and then I call fork to create a child and execute the command. Im working on this in ubuntu where most of the commands are in the /bin/ directory, so I append the program name (for example /bin/ls) and use that for the first arg of execvp and then I give it the argv array. My program works if I type in the command "ls", but when trying other commands or even "ls -l" I'm getting an "ls: invalid option." Im not sure what I'm doing wrong here.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define BUFFER_LEN 1024

int main(){
    char line[BUFFER_LEN];  //get command line
    char* argv[100];        //user command
    char* path= "/bin/";    //set path at bin
    char progpath[20];      //full file path
    int argc;               //arg count

while(1){

    printf("My shell>> ");                    //print shell prompt

        if(!fgets(line, BUFFER_LEN, stdin)){  //get command and put it in line
        break;                                //if user hits CTRL+D break
    }
    if(strcmp(line, "exit\n")==0){            //check if command is exit
        break;
    }

    char *token;                  //split command into separate strings
    token = strtok(line," ");
    int i=0;
    while(token!=NULL){
        argv[i]=token;      
        token = strtok(NULL," ");
        i++;
    }
    argv[i]=NULL;                     //set last value to NULL for execvp

    argc=i;                           //get arg count
    for(i=0; i<argc; i++){
        printf("%s\n", argv[i]);      //print command/args
    }
    strcpy(progpath, path);           //copy /bin/ to file path
    strcat(progpath, argv[0]);            //add program to path

    for(i=0; i<strlen(progpath); i++){    //delete newline
        if(progpath[i]=='\n'){      
            progpath[i]='\0';
        }
    }
    int pid= fork();              //fork child

    if(pid==0){               //Child
        execvp(progpath,argv);
        fprintf(stderr, "Child process could not do execvp\n");

    }else{                    //Parent
        wait(NULL);
        printf("Child exited\n");
    }

}
} 

Answer 1

The invalid option is because fgets() keeps the '\\n' when you press enter, try this

if(!fgets(line, BUFFER_LEN, stdin))
    break;
size_t length = strlen(line);
if (line[length - 1] == '\n')
    line[length - 1] = '\0';

when you are trying to call ls -l you are passing "-l\\n" as the option, hence the message.

You will have to change

strcmp(line, "exit\n")

to

strcmp(line, "exit")