Play Framework：混合Java和Scala控制器/视图

Question

There is a setting .enablePlugins(PlayScala) in the built.sbt file that sets my project to scala.

Now I want to use Java as well. I found that there are two versions of data.Form (play.data._ and import play.api.data._). So I used the fully qualified type for the parameter list.

@(loginForm: play.data.Form[User_LoginForm])

@import helpers._

@helper.form(action = routes.ApplicationJava.login(), 'id -> "loginForm") {
@helper.inputText(loginForm("username"))
@helper.inputPassword(loginForm("password"))
}

But now I have the same problem with the helper functions and I don't know what the fully qualified name for helper is so that they work with play.data.Form (Java).

Is there a way to use the helper functions for Java even when the project is set to scala?

Edit:

The error message for this line >> @helper.inputText(loginForm("username")) << is:

type mismatch; found : play.data.Form.Field required: play.api.data.Field

Edit:

Here is the corresponding part of my Java contoller.

public static Result showForm() {

    Form<User_LoginForm> userForm = play.data.Form.form(User_LoginForm.class);
    User_LoginForm ulf = new User_LoginForm();
    ulf.username = "abc";
    userForm = userForm.fill(ulf);

    return ok(views.html.userLoginJava.render(userForm));
}

Answer 1

PlayMagicForJava is supposed to implicitly convert your play.data.Form.Field into play.api.data.Field

implicit def javaFieldtoScalaField(jField: Field): Field

Implicit conversion of a Play Java form Field to a proper Scala form Field.

link to api