[英]ace editor find code snippet
i have setup ace to render html code let's say for example that he renderer the following code 我设置了ace来呈现html代码,例如,他渲染了以下代码
1 <html>
2 <body>
3 <table>
4 <tr>
5 <td>
6 test
7 </td>
I would like to get the line number for a given fragment of my code, so for example if i search 我想获取给定代码片段的行号,例如,如果我搜索
"<html><body><table><tr><td>"
i would like to move the cursor and higlight line 6. Unfortunately ace built in find function only seems to find code that are at the same line so 我想移动光标和高光6行。不幸的是,内置于find函数中的ace似乎只能找到同一行的代码,因此
ace.find('<html>', options)
work and highlight line 1 but 工作并突出显示第1行,但
ace.find('<html><body>', options)
doesn't find anything at all. 根本找不到任何东西。
Could you explain me why or give me a workaround ? 您能解释一下为什么还是给我解决方法? Thanks by advance ;)
预先感谢;)
if <html>
and <body>
are on different lines you need to search for ace.find('<html>\\n<body>', options)
(with \\n
) 如果
<html>
和<body>
在不同的行上,则需要搜索ace.find('<html>\\n<body>', options)
(带有\\n
)
another way is to use regexp to find offset you want in the editor.getValue()
string, and use 另一种方法是使用regexp在
editor.getValue()
字符串中查找所需的偏移量,然后使用
pos = session.doc.indexToPosition(100)
session.selection.moveToPosition(pos)
to move cursor to it 将光标移到它
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