[英]orientdb sql query to select edge and vertex fields property.
I do have following database structure. 我确实有以下数据库结构。
users -> comment -> products 用户 - >评论 - >产品
a. 一个。 users and products are the vertexes that contain some info etc: user_name, product_name and .... b.
用户和产品是包含一些信息等的顶点:user_name,product_name和.... b。 comment is the edge that contains comment and created/modified date.
comment是包含注释和创建/修改日期的边缘。
what is the sql query may look like in order to show the following result. 什么是sql查询可能看起来像是为了显示以下结果。
Note: i have to show all of the products that may have or no have comment. 注意:我必须显示可能有或没有评论的所有产品。
create class User extends V
create property User.name string
create class Product extends V
create property Product.name string
create class Comment extends E
create property Comment.comment string
create property Comment.createDate datetime
create property Comment.modifiedDate datetime
create vertex User set name = 'u1' # 12:0
create vertex Product set name = 'p1' # 13:0
create vertex Product set name = 'p2' # 13:1
create edge Comment from #12:0 to #13:0 set comment = 'nice product', createDate = sysdate()
If the above is your situation, I believe the query you're looking for is something like: 如果您的情况如上,我相信您正在寻找的查询类似于:
select *, expand(inE('Comment')) from Product
UPDATE: 更新:
It's not very pretty, but as a workaround you could use: 它不是很漂亮,但作为一种解决方法,您可以使用:
select *, inE('Comment').include('comment', 'createDate', 'modifiedDate') from Product
you cannot "join" classes/tables when querying. 查询时不能“加入”类/表。 instead, merge the result sets -> start from the edge class for
Product
s with Comment
s, then use let
and unionall()
to add the non- Comment
ed Product
s before expand()
ing: 相反,合并结果集 - >从
Product
s的edge类开始,使用Comment
s,然后使用let
和unionall()
在expand()
之前添加非Comment
ed Product
:
select expand($c)
let $a = (select in.name as name, out.name as User, comment, createDate, modifiedDate from Comment),
$b = (select from Product where in_Comment is null),
$c = unionall($a, $b)
note that in the result set you will have the @CLASS
field fed with null
s from the first query (ie, from the $a
result set) and with Product
from the second query (the $b
result set) 请注意,在结果集中,您将从第一个查询(即,从
$a
结果集)和第二个查询中的Product
( $b
结果集)中获取带有null
的@CLASS
字段
using @vitorenesduarte schema the following query may fit the current requirement 使用@vitorenesduarte模式,以下查询可能符合当前要求
select name AS product_name,in(comment).name
AS user_name,inE(comment).comment
AS comment,inE(comment).createDate
AS comment_created_date,inE(comment).modifiedDate
AS comment_modified_date from product
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