[英]Replace to another column if exits in MySql
I have a HTML table having values from Mysql. 我有一个具有Mysql值的HTML表。 My HTML table looks like this
我的HTML表格如下所示
------- ------ ------ ------
type name b_id Edit
------- ------ ------ ------
Laptop mac E1:23 edit
Desktop dell D2:45 edit
I am inserting values from input textboxes for type and name. 我正在从输入文本框中插入类型和名称的值。 And a select dropdown for b_id.
并为b_id选择下拉菜单。 I can edit each row values by clicking
edit
and i have a dropdown displaying all my b_id's
. 我可以通过单击“
edit
来编辑每行的值,并且有一个下拉列表显示所有b_id's
。
I need to update b_id values so that, if it already exists replace with new delete the old. 我需要更新b_id值,以便如果它已经存在,请用新的删除旧的替换。
For suppose i'l hit edit on Desktop dell row. 假设我要点击“ 桌面” dell行上的“ edit”。 And i'l select E1:23(which is already mapped for laptop mac ).
然后我选择E1:23(已经为笔记本电脑mac映射了)。 On saving this, E1:23 should map to desktop dell and previous mapping (laptop mac) should be deleted .
保存时, E1:23应该映射到桌面Dell,并且应该删除以前的映射(laptop mac)。 I mean it should be empty
我的意思是应该是空的
My Query 我的查询
$id = $_REQUEST['id']; // Auto Increment
$b_id = $_REQUEST['b_id']; //b_id from select dropdown on edit
$sql = "SELECT * FROM table_name WHERE b_id='$b_id'";
$rs=parent::_executeQuery($sql);
$rs=parent::getAll($rs);
if($rs) // if b_id already exists
{
//First empty old b_id which has mapped already
$sql2 = "UPDATE table_name SET b_id='$b_id' WHERE id='$id'";
$rs=parent::_executeQuery($sql);
}
So how to empty previous mapped b_id. 那么如何清空以前映射的b_id。 Not the type and name
不是类型和名称
If you want to empty the data in b_id, your query should be something like this: 如果要清空b_id中的数据,则查询应如下所示:
if($rs) // if b_id already exists
{
//First empty old b_id which has mapped already
$sql2 = "UPDATE table_name SET b_id='' WHERE b_id='$b_id'";
$rs=parent::_executeQuery($sql2);
}
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