[英]How do would I register this in Castle Windsor?
public interface IDo
{
... details
}
public class DoOneThing : IDo
{
...
}
public class DoAnotherThing : IDo
{
....
}
public interface IFooService
{
... details
}
public class FooService
{
private IDo do;
public FooService(IDo do)
{
// instance is of type specifically resolved per call
this.do = do;
}
...
}
Container.Register(ComponentFor<IDo>().ImplementedBy<DoOneThing>().Named("DoOneThing");
Container.Register(ComponentFor<IFooService>().ImplementedBy<FooService>().DependsOn(Dependency.OnComponent(typeof(IDo), "DoOneThing")).Named("DoItWithOneThing");
Container.Register(ComponentFor<IFooService>().ImplementedBy<FooService>().DependsOn(Dependency.OnComponent(typeof(IDo), "DoAnotherThing")).Named("DoItWithAnotherThing");
Container.Resolve<IFooService>("DoItWithOneThing");
How Do I register FooService to have a dependency of type IDo and then resolve with a specific implementation type? 如何注册FooService使其具有IDo类型的依赖关系,然后使用特定的实现类型进行解析? I've tried using something like the code above but I get an exception that no component for service can be found.
我尝试使用类似上面的代码的方法,但是出现一个例外,即找不到服务组件。 If I try to resolve to the named instance then it tells me that it's waiting for dependencies of DoOneThing.
如果我尝试解析为命名实例,则它告诉我它正在等待DoOneThing的依赖项。
You can use the typed Dependency.OnComponent
as mentioned in Castle Windsor - multiple implementation of an interface . 您可以使用Castle Windsor中提到的类型化的
Dependency.OnComponent
接口的多重实现 。
See also: Castle Project -- Inline dependencies 另请参阅: Castle Project-内联依赖项
var container = new WindsorContainer();
container.Register(
Component
.For<IDo>()
.ImplementedBy<DoAnotherThing>());
container.Register(
Component
.For<IDo>()
.ImplementedBy<DoOneThing>());
container.Register(
Component
.For<IFooService>()
.ImplementedBy<FooService>()
.Named("DoItWithOneThing")
.DependsOn(
Dependency.OnComponent<IDo, DoOneThing>()));
container.Register(
Component
.For<IFooService>()
.ImplementedBy<FooService>()
.Named("DoItWithAnotherThing")
.DependsOn(
Dependency.OnComponent<IDo, DoAnotherThing>()));
Test 测试
var doItWithOneThing = container.Resolve<IFooService>("DoItWithOneThing");
var doItWithAnotherThing = container.Resolve<IFooService>("DoItWithAnotherThing");
Console
.WriteLine(
"doItWithOneThing.Do is DoOneThing // {0}",
doItWithOneThing.Do is DoOneThing);
Console
.WriteLine(
"doItWithAnotherThing.Do is DoAnotherThing // {0}",
doItWithAnotherThing.Do is DoAnotherThing);
Output 产量
doItWithOneThing.Do is DoOneThing // True
doItWithAnotherThing.Do is DoAnotherThing // True
Declarations 声明
public interface IDo {}
public class DoOneThing : IDo {}
public class DoAnotherThing : IDo {}
public interface IFooService
{
IDo Do { get; }
}
public class FooService : IFooService
{
public FooService(IDo @do)
{
Do = @do;
}
public IDo Do { get; private set; }
}
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