十六进制值后拆分字符串

Question

My string:

 str1 = "Text\x11\x05\x11MoreTEXT\x02HELLO\x011"

I want to get all strings between \\xYY. I would like to get a list like this:

list1 = ["Text", "MoreTEXT", "HELLO", "1"]

Notice that \\xYY can occure more times in a row like in my example at the beginning. How can I split it like I want it?

Answer 1

You're close!

str_split = re.split('[\x01-\x1f\x7f]', str1)
str_lst = [s for s in str_split if s != '']

The first line splits the list, however it returns '' list elements if there are consecutive delimiters. The second line removes the blank elements from the list.

Answer 2

Try this technique. Just substitute the hex values with spaces, then split at a series of spaces.

new_string = re.split('\s+', re.sub('[\x01-\x1f\x7f]', ' ', str1))