获取内置函数的方法名称，该方法名称作为参数传递并在函数体内调用

Question

I'm looking to generalize the logging activity in python in my work.

Rather than calling logger.debug(), logger.info(), logger.warning() etc, I'm thinking of writing a template function which get all the necessary arguments to call either debug , info or warning etc.

Example:

def logging_template(logger_name, level, message):
    logger = logging.getLogger(logger_name)
    logger.##level(message) //Here if level is passed as debug then logger.debug should be called. If level is passed as info then logger.info should be called.
Similarly if warning or error or critical is passed then corresponding logger calls should be triggered.

I'm not interested on IF-ELSE block or condition checks. ##level should be replaced by the argument i'm passing.

Answer 1

Use getattr, for example:

def logging_template(logger_name, level, message):
    logger = logging.getLogger(logger_name)
    getattr(logger, level)(message)

Explanation:

getattr(logger, level) returns the function logger.debug if level is the string "debug". It returns logger.error if level is the string "error", and so on.

Answer 2

Why don't you just use the logger.log method? It takes a variable level and would seem to do the same as you're trying to do here.