[英]Java socket programming writebytes to readline
I am trying to get a java server and client communicating. 我想让一个java服务器和客户端进行通信。 For streaming data to the server I have this code:
为了将数据流传输到服务器,我有以下代码:
Socket ClientSocket = null;
ClientSocket = new Socket(IPAddress, portInt);
DataOutputStream outToClient = new DataOutputStream(ClientSocket.getOutputStream());
outToClient.writeBytes(command);
outToClient.flush();
And for the server I have: 对于我有的服务器:
ServerSocket mysocket = new ServerSocket(8081);
Socket connectionsocket = mysocket.accept();
BufferedReader inFromClient =
new BufferedReader(new InputStreamReader(connectionsocket.getInputStream()));
DataOutputStream outToClient = new DataOutputStream(connectionsocket.getOutputStream());
//program hangs here, client not sending
GetRequest = inFromClient.readLine();
System.out.println("Received: " + GetRequest);
These are only short portions of the overall code, I have found that the program hangs on the server side when the readLine(); 这些只是整个代码的一小部分,我发现当readLine()时程序挂在服务器端; is reached.
到达了。 I am trying to send data with writeBytes(command);
我试图用writeBytes(命令)发送数据; where command is a string.
其中command是一个字符串。 Any suggestions?
有什么建议么? thanks.
谢谢。
writebytes to readline
readbytes到readline
Stop right there. 停在那儿。 If you're using
readLine()
you're using BufferedReader
, which is a Reader
, which means you should be using a Writer
to talk to it, which means you should be using a BufferedWriter
, and as you're reading lines you must write lines, which means writing a line terminator (which you aren't presently doing), which means you should use BufferedWriter.newline()
. 如果您正在使用
readLine()
那么您正在使用BufferedReader
,这是一个Reader
,这意味着您应该使用Writer
与它通信,这意味着您应该使用BufferedWriter
,并且当您正在读取BufferedWriter
,您必须写行,这意味着写一个行终止符(你当前没有这样做),这意味着你应该使用BufferedWriter.newline()
。
Or PrintWriter.println(),
but don't forget to check for errors, as it swallows exceptions. 或
PrintWriter.println(),
但不要忘记检查错误,因为它吞下异常。
Don't directly use readLine
不要直接使用
readLine
Instead try this 而是试试这个
If( inFromClient.ready()){
// read string here.
}
It might be possible that buffer is not ready and you are trying to read. 缓冲区可能没有准备就绪并且您正在尝试阅读。 So it can create problem.
所以它可以创造问题。
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