在Windows命令行上运行Java程序1000次

Question

So I have a java program... it takes two arguments and I need to run it 1000 times. The first argument doesn't change, but the second one needs go to from 1 to 1000. How do I do this? I've been trying to figure this out for a long while now :(

Thanks in advance.

Answer 1

Modify the program to take three arguments instead of two. Then use the second and third arguments to form a loop.

Originally your program maybe like:

public static void main(String[] args) {
    String arg1 = args[0];
    String arg2 = args[1];

    //process using arg1 and arg2
}

Change it to the following:

public static void main(String[] args) {
    String arg1 = args[0];
    String arg2 = args[1];
    String arg3 = args[2];

    int loopstart = Integer.parseInt(arg2);
    int loopend = Integer.parseInt(arg3);

    for (int i = loopstart; i <= loopend; i++) {
        //process using arg1 and i <-- take note
    }
}

Note: Repeatedly calling the program from a loop in a batch file is much slower, and less desirable than actually using a loop within the program itself.

Answer 2

You can write a loop inside a .bat file and call the java program from it. Something like:

for /l %x in (1, 1, 1000) do (
 echo %x
 // call java using %x for the value of the current iteration
)

Calling java: How to run java application by .bat file