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如何销毁heatmap.js实例?

[英]How to destroy heatmap.js instance?

I'm using patrick wied's heatmapjs . 我正在使用patrick wied的heatmapjs I want to know how to destroy an instance and remove the canvas div created by h337.create(configObject) function. 我想知道如何销毁实例并删除由h337.create(configObject)函数创建的canvas div。

Example: 例:

var config = {
  container: document.getElementById('heatmapContainer'),
  radius: 10
};
var config2 = {
  container: document.getElementById('heatmapContainer'),
  radius: 5
};
var heatmapInstance1 = h337.create(config);
var heatmapInstance2 = h337.create(config);
var heatmapInstance3 = h337.create(config2);

I want to destroy and delete canvas div only for heatmapInstance1 instance. 我想仅为heatmapInstance1实例销毁和删除canvas div。

Currently there is no method to destroy a heatmapjs instance, but we can do that manually. 目前没有方法可以销毁heatmapjs实例,但我们可以手动完成。

First we have to remove the canvas element from DOM and than unset or destroy the heatmapjs instance. 首先,我们必须从DOM删除canvas元素,然后取消设置或销毁heatmapjs实例。

Example: 例:

//find corresponding canvas element
var canvas = heatmapInstance1._renderer.canvas;
//remove the canvas from DOM
$(canvas).remove();
//than unset the variable
heatmapInstance1 = undefined;
//or
heatmapInstance1 = null;

If you are using React component then you may have to do this in your componentWillReceiveProps(newProps) when dynamically sending new data to heatmap component. 如果您正在使用React组件,则在将新数据动态发送到热图组件时,可能必须在componentWillReceiveProps(newProps)中执行此操作。

this.heatmap._renderer.canvas.remove()
this.heatmap = Heatmap.create({container: ReactDOM.findDOMNode(this)})
this.setData(newProps.max, newProps.data);

You can add this function to CesiumHeatmap.js and use it to clear the heatmap: 您可以将此函数添加到CesiumHeatmap.js并使用它清除热图:

CHInstance.prototype.deleteLayer = function () {
    if (CesiumHeatmap.defaults.useEntitiesIfAvailable && this._cesium.entities) {
        if (this._layer) {
            this._cesium.entities.remove(this._layer);
        }
    } else {
        if (this._layer) {
            this._cesium.scene.imageryLayers.remove(this._layer);
        }
    }
};

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