[英]fetch values from different index value in array
I have an array and through it i wish to fetch values and store them in database. 我有一个数组,通过它我希望获取值并将它们存储在数据库中。
Array
(
[success] => 1
[products] => Array
(
[0] => Array
(
[id] => 373
[categories] => Array
(
[0] => 1
[1] => 15
[2] => 28
)
)
[1] => Array
(
[id] => 210
[categories] => Array
(
[0] => 15
[1] => 28
)
)
[3] => Array
(
[id] => 209
[categories] => Array
(
[0] => 15
[1] => 28
[2] => 15
)
)
)
)
)
I have fetched all the data, but now i am facing problem in fetching category. 我已经获取了所有数据,但现在我在获取类别方面遇到了问题。 i have table who's view is like this 我有桌子谁的观点是这样的
id prod_id prod_name product_catid product_subcatid
In this array the value 15 is for product_catid and 28 stands for product_subcatid. 在此数组中,值15表示product_catid,28表示product_subcatid。
part of code through which i was fetching values is, 我获取值的代码的一部分是,
if (!empty($array))
{
foreach ($array['products'] as $product)
{
if(isset($product['categories']))
{
$product_catid = $product['categories'][1];
$product_subcatid = $product['categories'][2];
$inserts1 = mysql_query("insert into product_category(prod_id,prod_name,product_catid,product_subcatid,product_subsubcatid) values ('".$idd."','".$product_name."','".$product_catid."','".$product_subcatid."','".$product_subsubcatid."')");
$posts[0]['message'] = 'Registered';
}
}
}
But the issue is in the second array ie [1], the value of product_catid has shifted to [0] index value and product_subcatid has shifted to [1] index value. 但问题在于第二个数组,即[1],product_catid的值已转移到[0]索引值,而product_subcatid已转移到[1]索引值。 Now i am stuck and am not able to understand how should i fetch and store values. 现在我陷入困境,无法理解我应该如何获取和存储值。 would appreciate some help. 会很感激一些帮助。
If your subcat
will always fall last, and the cat
will follow that previously, just use array_pop
instead of pointing to it explicitly. 如果您的subcat
总是落在最后,并且cat
将遵循之前的那个,那么只需使用array_pop
而不是明确地指向它。 Rough example: 粗略的例子:
if (!empty($array)) {
foreach ($array['products'] as $k => $product) {
if(isset($product['categories'])) {
$product_subcatid = array_pop($product['categories']);
$product_catid = array_pop($product['categories']);
$db = new PDO('mysql:host=localhost;dbname=database_name', 'username', 'password');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$insert = $db->prepare('INSERT INTO product_category (prod_id,prod_name,product_catid,product_subcatid,product_subsubcatid) VALUES (?, ?, ?, ?, ?)');
$insert->execute(array($idd, $product_name, $product_catid, $product_subcatid, $product_subsubcatid));
}
}
}
Another way would be to just reverse it: 另一种方法是反转它:
$product['categories'] = array_reverse($product['categories']);
$product_subcatid = $product['categories'][0];
$product_catid = $product['categories'][1];
An alternative solution: 替代解决方案:
$product_subcatid = end($product['categories']);
$product_catid = prev($product['categories']);
This way you don't modify the array. 这样您就不会修改数组。
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