[英]SQL joining three tables and split into columns
I have three tables, mess_stock
, mess_voucher
, add_grocery
. 我有三个表,
mess_stock
, mess_voucher
和add_grocery
。
Mess_stock table is below, 下表为Mess_stock,
+-----+------------+-----------------+-----------------+--------+---------+---------+------------+----------+
| sno | voucher_id | particular_name | opening_balance | inward | outward | balance | pay_amount | pay_type |
+-----+------------+-----------------+-----------------+--------+---------+---------+------------+----------+
| 49 | 5 | 4 | 100 | 10 | 100 | 10 | 10.00 | 1 |
| 50 | 17 | 5 | 111 | 10 | 20 | 101 | 60.00 | 1 |
| 51 | 7 | 3 | 123 | 2 | 1 | 124 | 300.00 | 1 |
| 52 | 7 | 1 | 123 | 20 | 20 | 123 | 500.00 | 2 |
| 53 | 14 | 8 | 100 | 5 | 95 | 10 | 60.00 | 2 |
+-----+------------+-----------------+-----------------+--------+---------+---------+------------+----------+
Mess_voucher table is below 下面是Mess_voucher表
+------------+--------------+--------------+
| voucher_id | voucher_name | voucher_date |
+------------+--------------+--------------+
| 5 | VG1001 | 2015-02-19 |
| 6 | VG1001 | 2015-02-20 |
| 7 | VG1002 | 2015-02-20 |
| 8 | VG1002 | 2015-02-19 |
| 9 | MS1001 | 2015-02-20 |
| 10 | VG10012 | 2015-02-19 |
| 11 | 0 | 2015-02-23 |
| 12 | 1 | 2015-02-24 |
| 13 | MS1001 | 2015-02-25 |
| 14 | MS1001 | 2015-02-28 |
| 15 | VG1003 | 2015-02-28 |
| 16 | MS1001 | 2015-02-19 |
| 17 | MS1001 | 2015-02-21 |
+------------+--------------+--------------+
Add_grocery table is below Add_grocery表在下面
+-----+-----------------+------------------+
| sno | particular_name | particular_price |
+-----+-----------------+------------------+
| 1 | Rice | 25.00 |
| 3 | Mango | 150.00 |
| 4 | Coconut | 22.00 |
| 5 | Banana | 6.00 |
| 6 | Raddish | 12.00 |
| 7 | Apple | 150.00 |
| 8 | Pumkin | 12.00 |
+-----+-----------------+------------------+
I want to group the sum of pay_amount of mess_stock table. 我想将mess_stock表的pay_amount总和分组。 I have used the below query
我用下面的查询
SELECT opening_balance AS ope_stock,
balance AS clo_stock,
SUM(IF(pay_type = 1, pay_amount, 0)) mess_pay,
SUM(IF(pay_type=2, pay_amount, 0)) est_pay
FROM mess_stock;
That works fine. 很好 The particular_name is the auto increment id of add_grocery table.
specific_name是add_grocery表的自动增量ID。 I need the inward outward amount total.
我需要总共向内的金额。 For example the inward amount 10 means it has to get the
particular_price
from add_grocery
using the particular_name
provided in the mess_stock
table, similarly I need all the answer. 例如向内量10意味着它必须得到
particular_price
从add_grocery
使用particular_name
在提供mess_stock
表,同样我需要所有的答案。 And I want to sort that by date wise. 我想按日期排序。 The date of the entry is stored in the
mess_voucher
table that is connected to mess_stock
table. 的条目的日期被存储在
mess_voucher
连接到表mess_stock
表。
Try this it will work : 试试这个将起作用:
Use Inner Join : 使用内部联接:
SELECT t2.`particular_name`,t1.`inward`,t1.`outward`,t2.`particular_price`,t3.`voucher_date` from Mess_stock t1 JOIN Add_grocery t2 ON t1.`particular_name`=t2.`sno` JOIN Mess_voucher t3 ON t3.`voucher_id`=t1.`voucher_id` ORDER BY t3.`voucher_date` DESC
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