[英]Multiple joins between only two tables
Table1: key_item#, code_1, code_2, code_3 表1:key_item#,code_1,code_2,code_3
Table2: uniq_code, code_desc 表2:uniq_code,code_desc
Table1: 表格1:
key_item# code_1 code_2 code_3
1 Y01 M02 X01
2 Y01 M04 X01
Table2: 表2:
uniq_code code_desc
Y01 DescriptionY01
M02 DescriptionM02
X01 DescriptionX01
M04 DescriptionM04
Better image detail https://dl.dropboxusercontent.com/u/9951225/Untitled-4.jpg 更好的图像细节https://dl.dropboxusercontent.com/u/9951225/Untitled-4.jpg
Query Result 查询结果
key_item# code_1 code_desc code_2 code_desc cod_3 code_desc
1 Y01 DescriptionY01 M02 DescriptionM02 X01 DescriptionX01
2 Y01 DescriptionY01 M04 DescriptionM04 X01 DescriptionX01
Query 询问
SELECT Table1.key_item#,
Table1.code_1,
Table2.code_desc,
Table1.code_2,
Table2.code_desc,
imc_iamerican_claim_lines.Add_diagnosis1
FROM msp_dx9_priority.dx09code_matrix
INNER JOIN Table1 ON Table1.code_1 = Table2.uniq_code
INNER JOIN Table1 ON Table1.code_2 = Table2.uniq_code
I can't go over the "Not unique table Alias" error 我无法查看“非唯一表别名”错误
You need to alias your joins, so that the query engine knows how to disambiguate the first Table1 from the second Table1. 您需要为联接加上别名,以便查询引擎知道如何从第二个Table1消除第一个Table1的歧义。 Documentation here: http://dev.mysql.com/doc/refman/5.0/en/join.html
此处的文档: http : //dev.mysql.com/doc/refman/5.0/en/join.html
Here is an example: 这是一个例子:
SELECT Table1.key_item#, -- which join should this come from? code1 or code2?
t1_code1.code_1,
Table2.code_desc, -- don't know what is Table2, perhaps t1_code1?
t1_code2.code_2,
Table2.code_desc, -- don't know what is Table2, perhaps t1_code2?
imc_iamerican_claim_lines.Add_diagnosis1 -- also don't know what this is :)
FROM msp_dx9_priority.dx09code_matrix
INNER JOIN Table1 t1_code1 ON t1_code1.code_1 = Table2.uniq_code
INNER JOIN Table1 t1_code2 ON t1_code2.code_2 = Table2.uniq_code
I found this approach 我发现这种方法
SELECT t1.key, t1.code_1, t21.`desc` as desc_1, t1.code_2, t22.`desc` as desc2, t1.code_3, t23.`desc` as desc3 FROM t1 LEFT JOIN t2 t21 on t1.code_1 = t21.code LEFT JOIN t2 t22 ON t1.code_2 = t22.code LEFT JOIN t2 t23 ON t1.code_3 = t23.code;
With this reference I did my final report. 以此参考,我完成了最终报告。 Just in case someone is going to need it.
以防万一有人需要它。
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