[英]mysql - returns false on valid INSERT syntax
I tried to figure out an error thrown by mysql here, but I do not know on how to solve this issue. 我试图找出mysql抛出的错误,但我不知道如何解决这个问题。 I had the same problem before but it was only caused by invalid syntax in values variable, but this time round I cannot find what's wrong with it.
我以前遇到过同样的问题但它只是由值变量中的无效语法引起的,但这一次我找不到它的错误。 Can anyone help me out please?
有人可以帮帮我吗?
My mysql table: 我的mysql表:
CREATE TABLE IF NOT EXISTS `merit` (
`id` int(11) NOT NULL,
`id_user` text,
`id_num` text,
`category` text,
`timeoccur` text,
`location` text,
`remarks` text
)
ALTER TABLE `merit`
ADD PRIMARY KEY (`id`);
ALTER TABLE `merit`
MODIFY `id` int(11) NOT NULL AUTO_INCREMENT;
The php code: php代码:
function add_merit($d) {
//id_user,id_num,type,time_occur,venue,description
global $con; //this global tested and works
foreach ($d as $k=>$v) {
if ($v == "") {
header('location: merit.php?method=error');
die();
}
else {
continue;
}
}
$ic = $d['ic'];
$type = $d['type'];
$loc = $d['loc'];
$rem = $d['rem'];
$uid = uid(); // function call on other php, tested and works
$rs = $con->query("INSERT INTO merit(id_user,id_num,category,timeoccur,location,remarks) VALUES ('$uid','$ic','$type','$loc','$rem')");
die(var_dump($rs)); //this returns false
if ($rs) {
//header('location: merit.php?method=success');
die('ok');
}
else {
//header('location: merit.php?method=error');
die('err');
}
}
你还没有传递字段变量: -
$rs = $con->query("INSERT INTO merit(id_user,id_num,category,timeoccur,location,remarks) VALUES ('$uid','$ic','$type','$loc','$rem')");
You are selecting 6 fields for insertion and passing 5 values 您正在选择6个字段进行插入并传递5个值
columns :- id_user,id_num,category,timeoccur,location,remarks
values :- '$uid','$ic','$type','$loc','$rem'
so have a look and send proper values in query. 所以看看并在查询中发送适当的值。
你有6个字段值。缺少一个字段
$rs = $con->query("INSERT INTO merit(id_num,category,timeoccur,location,remarks) VALUES ('$uid','$ic','$type','$loc','$rem')");
The reason why you are getting this wrong is because you tell mysql to edit 6 table fields but you are only giving it 5 VALUES(). 你错误的原因是你告诉mysql编辑6个表字段,但你只给它5个VALUES()。 They both have to equal the same amount.
它们都必须等于相同的数量。
在查询中,您必须传递6个字段,并且您传递了5个字段,因此请按如下方式更新查询:
$rs = $con->query("INSERT INTO merit(id_num,category,timeoccur,location,remarks) VALUES ('$uid','$ic','$type','$loc','$rem')");
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