在C中将int转换为char的问题

Question

I've wrote a small function for debug purpose which sends string via USB to a terminal :

void localprint(char* msg){
if(strlen(msg) > 60){
            usb_sendData(msg,60);
}
else usb_sendData(msg,strlen(msg));

} the function works fine for strings like :

localprint(" I'm a test" ), 

the message is displayed on terminal. Now I want to get the adcValue which is an int on the terminal, for I've tried :

char t= (char)(((int)'0')+getADCValue(9)); // getting the ADC value of 0th channel 
localprint(&t);

this doens't work at all , I'Ve also tried :

char t= (char) getADCVAlue(9);
localprint(&t);

it doesn't work neither. So my question is any idea how can I do that . I'm using uC STM32f10xx and ARM gcc. thanks for any hint

Answer 1

Without knowing anything about the range of possible ints, something like this will work:

char buffer[32];
sprintf(buffer, "%d", getADCVAlue(9));
localprint(buffer);

Since you did 0+ , I'm assuming it's one digit, so you could go

char buffer[2];
buffer[0] = '0' + getADCVAlue(9);
buffer[1] = '\0';
localprint(buffer);

Answer 2

Answer from John3136 will work fine if you replace sprintf with some lightweight implementation of this, eg xsprintf from elm-chan which I found extremely helpful in embedded programming. Or you must have some stubs for system calls like _sbrk if you want to use sprintf .

I can't comment solution from John3136 because I don't have enough reputation.