Android SQLiteDatabase.openDatabase返回路径而不是数据库本身

Question

I'm trying to open a database passed from a intent, when I try to open the DB it will return the DB path instead of the DB self, so when I try to perform SQLite commands it wont work

URI uri = (Uri) getIntent().getExtras().get(Intent.EXTRA_STREAM);
SQLiteDatabase oldDB = SQLiteDatabase.openDatabase(uri.getPath(), null, 1);
database.selectTable(oldDB)

//select table from old DB
selectTable(SQLiteDatabase oldDB){
       database.execSQL("SELECT * FROM " +
                       oldDB +
                       ".table1"
}

will result in error: SELECT * FROM SQLiteDatabase: /mnt/sdcard/path/to/database.db.table1 I need to get the actual Database "SELECT * FROM nameOfDatabase.table1"

Answer 1

when I try to open the DB it will return the DB path instead of the DB self

No, it does not. toString() on a SQLiteDatabase returns the path. You are concatenating toString() on a SQLiteDatabase in your query, for unknown reasons. If you want to perform a query on oldDB , call query() or rawQuery() on oldDB , not whatever database is.

Answer 2

The name of a database that you have opened with openDatabase is always main .

You get different database names only when you actually attach a database to another, ie, when you execute an ATTACH statement on a database.