如何在javascript中测试字符串是否包含带有正则表达式的数字？

Question

I'm trying with

function hasANumber(value) {
    return /^.*[0-9]*.*$/.test(value);
}

Where I was wrong?

Answer 1

* in regex means zero or more

You should have used + which means one or more, as in:

/^.*[0-9]+.*$/

Although this can be simplified to:

/[0-9]+/

Answer 2

Just \\d would be enough for this case.

> /\d/.test('foo')
false
> /\d/.test('fo1o')
true

[0-9]* in your regex matches a digit zero or more times, so it would allow also the strings which won't have a digit.

Answer 3

这是写数字正则表达式的正确形式：

 \d+$