按客户分组并按月份列透视查询显示的Mysql销售表

Question

I have a sales table with the following columns:

|  Customer_Id | amount |  date  |

What would be the best way to group data by customer_id , and displaying monthly total(SUM) of amount for each Customer_id (one row per Customer_id), on distinct month columns?

The desired output would be something like:

Customer     |January    | February   | March       | ....

Customer_id  |SUM amount | SUM amount | SUM amount | ....

I believe in Sql this is called a pivot table.

¡Thanks!

Answer 1

Let's say you have following table:

mysql> select * from sales;
+-------------+--------+------------+
| customer_id | amount | date       |
+-------------+--------+------------+
|           1 |     12 | 2015-01-01 |
|           1 |      1 | 2015-01-02 |
|           1 |    663 | 2015-02-12 |
|           2 |     22 | 2015-01-03 |
|           2 |     21 | 2015-02-12 |
|           2 |     11 | 2015-02-12 |
|           2 |      9 | 2015-04-12 |
+-------------+--------+------------+

You can do this using this query:

SELECT
  customer_id,
  sum(if(month(date) = 1, amount, 0))  AS Jan,
  sum(if(month(date) = 2, amount, 0))  AS Feb,
  sum(if(month(date) = 3, amount, 0))  AS Mar,
  sum(if(month(date) = 4, amount, 0))  AS Apr,
  sum(if(month(date) = 5, amount, 0))  AS May,
  sum(if(month(date) = 6, amount, 0))  AS Jun,
  sum(if(month(date) = 7, amount, 0))  AS Jul,
  sum(if(month(date) = 8, amount, 0))  AS Aug,
  sum(if(month(date) = 9, amount, 0))  AS Sep,
  sum(if(month(date) = 10, amount, 0)) AS Oct,
  sum(if(month(date) = 11, amount, 0)) AS Nov,
  sum(if(month(date) = 12, amount, 0)) AS `Dec`
FROM sales
GROUP BY customer_id;

And the output:

+-------------+------+------+------+------+------+------+------+------+------+------+------+------+
| customer_id | Jan  | Feb  | Mar  | Apr  | May  | Jun  | Jul  | Aug  | Sep  | Oct  | Nov  | Dec  |
+-------------+------+------+------+------+------+------+------+------+------+------+------+------+
|           1 |   13 |  663 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |
|           2 |   22 |   32 |    0 |    9 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |    0 |
+-------------+------+------+------+------+------+------+------+------+------+------+------+------+

Answer 2

Try this:

SELECT `Customer_id` AS Customer,
SUM(`amount`) AS MONTHNAME(`date`)
FROM `sales`
GROUP BY YEAR(`date`), MONTH(`date`);

Answer 3

MySQL provides the WITH ROLLUP modifier for the GROUP BY clause. Take a look at this.

... GROUP BY customer_id WITH ROLLUP

Hope it helps.

Answer 4

Try this code.

SELECT Customer_id , SUM(amount), MONTHNAME(date) FROM sales_table GROUP BY MONTH(date);

Answer 5

This query gets the desired result:

SELECT Customer_id,

Sum(CASE WHEN MONTH(date) = 1 THEN amount END) AS Jan,
Sum(CASE WHEN MONTH(date) = 2 THEN amount END) AS Feb,
Sum(CASE WHEN MONTH(date) = 3 THEN amount END) AS Mar,
...

FROM table_name

GROUP BY Customer_id

Thanks to @shawnt00 for the heads up ;)

Answer 6

If you change each line like this in the answer from Piotr

sum(if(month(date) = 1, amount, 0))  AS Jan,

to

sum(if((month(date) = 1 AND year(date) = 2017 ),  amount,0))  AS Jan_17,

you can split the table when there is more than a year of data