如何使用C＃从XmlDocument获取具有其属性且没有子节点的根节点

Question

I have an xml like:

<Customer id="">
 <Name />
 <Address />
</Customer>

I would like to select ONLY a root node header(not footer) with its attributes without its child nodes:

<Customer id="">

Answer 1

You can use Root property if it is root element:

XDocument Doc = XDocument.Parse(StringXML);

var RootNode= Doc.Root;
string NodeName = RootNode.Name.ToString();
string AttributeValue = RootNode.Attribute("id").Value;

if there are multiple Customer nodes in the xml then you have to use linq:

var nodes = from customer in Doc.Descendants("Customer")
                         select new { 
                                     NodeName = customer.Name.ToString(),               
                                     Id = customer.Attribute("id").Value 
                                    };

UPDATE:

For getting all attributes you can use Attributes() this way:

var nodess = from customer in Doc.Descendants("Customer")

             select new { 
                          NodeName = customer.Name.ToString(), 
                          Attributes = customer.Attributes() 
                        };

WORKING DOTNET FIDDLE EXAMPLE

Answer 2

If you just want to take this node as string, the you can use Root property, and then split root by Environment.NewLine and take the first one:

 XDocument xdoc = XDocument.Parse(InnerXML);
 var result = xdoc.Root.ToString()
                       .Split(new string[] {Environment.NewLine}, StringSplitOptions.None)
                       .First();

The result is: <Customer id="">

Additional1 :
If you want to get all attributes names and values which belong to root, then you can use:

var rootAttributesDatas = xdoc.Root
                         .Attributes()
                         .Select(x => new { AttributeName = x.Name, AttributeValue = x.Value })
                         .ToList();

Additional2 :
If you have more than one customer node and want to select all datas about them as a list:

var allCustomerNodeDatas = xdoc.Root.Descendants("Customer")
                           .Select(x => new
                            {
                                 NodeName = x.Name,
                                 AttributesDatas = x.Attributes().Select(attr => new
                                 {
                                     AttributeName = attr.Name,
                                     AttributeValue = attr.Value
                                 }).ToList()
                            }).ToList();