在Android中如何实现带有按钮的弹出屏幕。 单击按钮可调用活动中的不同功能

Question

I am developing a game in Android. The game is implemented in the MainActivity.java and uses Relative Layout in xml. I want to implement a pause button, which when clicked opens a pop-up window with buttons for options like "1 player","2 Player","Change skin",'Challenge Friend" etc.

1.How to create a layout at runtime with the buttons and can we destroy the layout when an option is clicked.

2.Can we get the id of the option button clicked in the dynamically created layout, to the MainActivity, so that the corresponding function can be called.

3.when dynamically creating the layout, will the values of the already existing layout be reset?

4.Is dynamically creating layout and destroying it very expensive?

I am new to android and so would really appreciate some help...Thankyou!!!

Answer 1

Sounds like you just need an alert dialog with three buttons? Use the onlick functions in this answer . If you need an image view in the pop up see this answer and use similar tactics.

Answer 2

如果要使用自定义布局的自定义对话框，请使用DialogFragment： http : //developer.android.com/reference/android/app/DialogFragment.html