[英]How to get cumulative sum by group
Here is desired result : 这是理想的结果:
At ID=14, I need to reset cum value add with new cum_value
. 在ID = 14时,我需要使用新的
cum_value
重置cum_value
。
SQL : (fiddle : http://sqlfiddle.com/#!6/62f01/14 ) SQL :(小提琴: http ://sqlfiddle.com/#!6/ 62f01/14 )
You were not so far, but I've try with less complicated queries : 你不是那么远,但我尝试了不那么复杂的查询:
DECLARE @t table(
id int
)
INSERT INTO @t (id)
VALUES (0),(1),(2),(3),(4),(5),(6),
(7),(8),(9),(10),(11),(12),(13),
(14),(15),(16),(17),(18),(19),
(20),(21),(22),(23),(24),(99);
SELECT *
,SUM(id)
OVER(ORDER BY id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Cum_STEPID
FROM @t
WHERE id < 14
UNION
SELECT *
,SUM(CASE WHEN id = 14 THEN 91000 ELSE id END)
OVER(ORDER BY id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Cum_STEPID
FROM @t
WHERE id >= 14
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.