[英]mysql single query to count multiple values
I need single query to count multiple status value... 我需要一个查询来计算多个状态值...
Table 表
+-------------+------------------+--------+
| ID | Name | Status |
+-------------+------------------+--------+
| 50 | Name1 | 1 |
| 49 | Name2 | 2 |
| 50 | Name1 | 1 |
| 49 | Name2 | 1 |
| 50 | Name1 | 2 |
| 50 | Name1 | 2 |
| 50 | Name1 | 3 |
| 50 | Name1 | 3 |
| 50 | Name1 | 1 |
+-------------+------------------+--------+
Expecting Out put: 预期输出:
+-------------+------------------+--------------+--------------+--------------+
| ID | Name | Cnt(Status1) | Cnt(Status2) | Cnt(Status3) |
+-------------+------------------+--------------+--------------+--------------+
| 50 | Name1 | 3 | 2 | 2 |
| 49 | Name2 | 1 | 1 | 0 |
+-------------+------------------+--------------+--------------+--------------+
I need query for the above output... 我需要查询上面的输出...
You can use conditional sum to do it 您可以使用条件和来做到这一点
select
id,
Name,
sum(Status=1) as cnt_status1,
sum(Status=2) as cnt_status2,
sum(Status=3) as cnt_status3
from table_name
group by id,Name
I gues this will do the trick: 我想这会成功的:
SELECT
ID,
Name,
COUNT(CASE WHEN Status = 1 THEN 1 ELSE 0 END),
COUNT(CASE WHEN Status = 2 THEN 1 ELSE 0 END),
COUNT(CASE WHEN Status = 3 THEN 1 ELSE 0 END)
FROM TABLE
GROUP BY
ID,
Name
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.