如何在python中获取具有特定文件夹兄弟的特定文件夹

Question

I would like to find the path to specific folders that have only specific folders brothers

ex: I want to find all folders named : zeFolder with siblings folders brotherOne and brotherTwo

|-dad1
|---brotherOne
|---brotherFour
|---zeFolder ( not match )

|-dad2
|---brotherOne
|---brotherTwo
|---zeFolder (♥♥♥Match♥♥♥)

[...]

Below is my code, but with this solution I find all the folders.

import os
for root, dirs, files in os.walk("/"):
    #print (dirs)
    for name in dirs:
        if name == 'totolo':
                print ('finded')
                print(os.path.join(root, name))

I don't know how to use Conditional Statements to do that

Thanks for you help.

Answer 1

Basically it sounds like you want to find a specific set of subfolders so using sets is both natural and makes this a fairly easy thing to do. Their use also removes order dependencies when checking for equality.

import os

start_path = '/'
target = 'zeFolder'
siblings = ['brotherOne', 'brotherTwo']
sought = set([target] + siblings)

for root, dirs, files in os.walk(start_path):
    if sought == set(dirs):
        print('found')

Answer 2

What about using lists

import os

folder = 'zeFolder'
brothers = ['brotherOne', 'brotherTwo']

for dirpath, dirnames, filenames in os.walk('/'):
    if folder in dirnames and all(brother in dirnames for brother in brothers):
        print 'matches on %s' % os.path.join(dirpath, 'zeFolder') 

or sets

import os

folder = 'zeFolder'
brothers = set(['brotherOne', 'brotherTwo', folder])

for dirpath, dirnames, filenames in os.walk('/'):
    if set(dirnames).issuperset(brothers) :
        print 'matches on %s' % os.path.join(dirpath, 'zeFolder') 

Both run at same speed for me.

Answer 3

import os
import glob

filelist = glob.glob(r"dad1/*brotherOne")
for f in filelist:
    print(f)

filelist = glob.glob(r"dad1/*brotherTwo")
for f in filelist:
    print(f)

You could also try the glob technique. And do whatever action you'd like to in the for loop.