将unique_ptr引用传递给boost :: bind？

Question

I'm on CentOS 6.6 (gcc 4.4.7) and developing with Boost.Asio (1.41). I'd like io_service to call member function run() in manger object m when it starts. The code I'm trying to compile looks like:

#include <memory>
#include <boost/asio.hpp>
#include <boost/bind.hpp>

boost::asio::io_service io;
std::unique_ptr<manager> m;
m = std::make_unique<manager>;
io.post(boost::bind(&manager::run, &m));

gcc pitches a fit on the boost::bind statement, which includes:

/usr/include/boost/bind/mem_fn_template.hpp:40: error: pointer to
member type ‘void (manager::)()’ incompatible with object type
‘std::unique_ptr<manager, std::default_delete<manager> >’

What do I want to be doing here?

The manager object will only know about timers; a separate object that knows about io_service will get added to its constructor later. But the idea is that manager::run() will create an initial set of timers to bootstrap the system.

Clarification:

My thinking here is that the outer block of code manages the lifetime of m and that the next statement will be io.run() . The outer code will destroy m when io.run() returns. Hence, passing a raw reference for m to io is appropriate. But I'm a modern C++ novice and could be way off base here.

Answer 1

You'd need C++-14 and generalized lambda capture to make this work -- you'd need to move the unique pointer into the lambda. Instead, just use a shared_ptr , which std::bind understands natively:

std::shared_ptr<manager> m;
m = std::make_shared<manager>();
io.post(std::bind(&manager::run, std::move(m)));

The std::move is optional but ensures that m doesn't keep the manager around when it's not wanted.