抽象类和接口Java

Question

Class A

public abstract class AbstractA {
 public abstract void method1(int a);
 public void method2() {
 System.out.println("method2");
 } // end method2
 public abstract void method3();
}

Class B

public abstract class AbstractB {
 public abstract void method3();
 public abstract void method4();
} 

Class C

public interface InterfaceC {
 void method1(int a, int b);
 void method2();
 void method4();
} 

Test

public abstract class Choice3 extends AbstractA implements InterfaceC {
 public void method1(int a) {}
 public void method4() {}
} // end class

I'm very confused as to why Choice 3 actually compiles. It does overload method1(int a), but doesn't actually overload method1(inta intb).

Answer 1

public abstract class Choice3 extends AbstractA implements InterfaceC 

当您的类iself是抽象的时，它不需要实现其直接/间接抽象父级的所有方法