[英]Replace all occurrences of * a string
I am trying to do string.replace()
on the *
character. 我正在尝试在
*
字符上执行string.replace()
。 The string has multiple occurrences of the character and so I need to do a global replace, but if I do what seems natural it produces the comment tag. 该字符串有多次出现的字符,因此我需要进行全局替换,但是如果我执行看起来很自然的操作,它将生成注释标记。
x.replace(/*/g, '');
How do you work around this? 您如何解决这个问题?
You'll need to escape the *
您需要转义
*
*
is a reserved lookup item: *
是保留的查找项目:
*
Matches the preceding character 0 or more times.*
与前面的字符匹配0次或更多次。 Equivalent to {0,}.等效于{0,}。
For example, /bo*/ matches 'boooo' in "A ghost booooed" and 'b' in "A bird warbled", but nothing in "A goat grunted".
例如,/ bo * /匹配“ A booooed”中的“ boooo”和“ A bird warbled”中的“ b”,但匹配“ Aunted grunt”中的任何内容。
var jamie = '* 8 * *';
jamie = jamie.replace(/\*/g, '');
// 8
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