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Linq to sql:连接和分组依据问题

[英]Linq to sql : Issues with Join and Group by

I'm having some trouble trying to achieve my "search" query. 我在尝试实现“搜索”查询时遇到了一些麻烦。 I read lots of posts but could not find how to do in my particular case. 我读了很多文章,但找不到适合我的特定情况的方法。 Here is my three tables overview with some values : 这是我的三张表概述,其中包含一些值:

Table Person : 表人:

Id OtherColumns...
1  ...
2  ...
3  ...

Table Job : 表工作:

Id PersonId OtherColumns...
1  1        ...
2  2        ...
3  3        ...

Table Skill : 餐桌技巧:

PersonId Discipline Value OtherColumns...
1        0          1    ...
1        2          2    ...
1        1          3    ...
2        2          4    ...
2        6          5    ...
2        3          6    ...
3        4          7    ...
3        7          8    ...

I would like to have : 我想拥有 :

Person Job TotalValues
1       1  6 (1+2+3)
2       2  15 (4+5+6)
3       3  15 (7+8)

I tried this : 我尝试了这个:

var result =
    from job in db.Job
    join person in db.Person
    on job.PersonId equals person.Id
    join skill in db.Skill
    on person.Id equals skill.PersonId
    group skill by skill.Value into sk
    select new
    {
        Person = ???
        Job = ???
        TotalValues = sk.Sum(s => s.Value)
    };

But don't know how to get back person and job references... "person" and "job" as defined in the join clause don't work. 但是不知道如何找回人和工作的引用……join子句中定义的“人”和“工作”不起作用。 I need those three because I have to perform multiple "where" and "order by" on it later, in my "search" function. 我需要这三个,因为稍后我必须在“搜索”功能中对其执行多个“ where”和“ order by”。

Does it have something to do with sk.Key.Something ? 它与sk.Key.Something有关吗?

If anyone has an idea I would be really, really thankful ! 如果有人有想法,我将非常感谢!

You need to group on multiple columns following way: 您需要按照以下方式对多个列进行分组:

group skill by new 
          { 
             skill.Value,
             person.PersonId,
             job.JobId
          } into g
   select new
        {
           Person =g.Key.PersonId,
           Job = g.Key.JobId,
           TotalValues = g.Sum(x=>x.Value)
        }

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