[英]SQL query date string by range
Spec: I need to query by date month and day only (ignoring year) 规格:我只需要按日期月份和日期查询(忽略年份)
Input: 输入:
start := '2015-12-29'
end := '2016-01-03'
Output: 输出:
1986-12-30
1980-01-01
1982-12-31
1978-01-03
...
Current solution: 当前解决方案:
SELECT *
FROM users
WHERE RIGHT(birthday,5) >= $1
AND RIGHT(birthday,5) <= $2
But this only works when the year not overlap, what's the easiest solution for this case? 但这仅在年份不重叠的情况下有效,这种情况最简单的解决方案是什么?
My simplest solution is by generating the SQL string using another language: 我最简单的解决方案是使用另一种语言生成SQL字符串:
if start_year == end_year {
date_where = `
AND RIGHT(birth_date,5) >= RIGHT(` + Z(start) + `,5)
AND RIGHT(birth_date,5) <= RIGHT(` + Z(end) + `,5)
`
} else {
date_where = `
AND ( RIGHT(birth_date,5) >= RIGHT(` + Z(start) + `,5)
AND RIGHT(birth_date,5) <= '12-31'
) OR ( RIGHT(birth_date,5) >= '01-01'
AND RIGHT(birth_date,5) <= RIGHT(` + Z(end) + `,5)
)`
}
I believe there are better way than this.. 我相信有比这更好的方法了。
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