如何获取mysql数据并以html显示

Question

I've created a database in mysql. 我已经在mysql中创建了一个数据库。 It works. 有用。 When a user goes to /upload.html...the user enters details: 当用户转到/upload.html ...时，用户输入详细信息：

first name :
last name:
email address:

and it gets stored in test2 database and person_list table. 并将其存储在test2数据库和person_list表中。 I've checked and it works. 我已经检查了并且可以正常工作。

However I'm trying to display this data on /download.html 但是我试图在/download.html上显示此数据

the data doesn't populate in the tables. 数据不会填充在表格中。

I'm trying to get it to look like this: 我正在尝试使其看起来像这样：

first name
Last name
email

first name
last name
email

first name
last name 
email and so forth...

I'm fairly new to php...and I know there are mistakes in this code..but can't pinpoint where.. 我对php很陌生...我知道这段代码中有错误..但无法查明位置..

I keep getting this: the php code keeps displaying in the page instead of the data showing in the tables 我不断得到这个：php代码一直显示在页面中，而不是表中显示的数据

在此处输入图片说明

this is download.html 这是download.html

---html code---
    <?php
    $hostdb = '************';
    $namedb = 'test2';
    $userdb = '**********';
    $passdb = '********';
    try {
      $conn = new PDO("mysql:host=$hostdb; dbname=$*****", $userdb, $passdb);
      $conn->exec("SET CHARACTER SET utf8");

      $sql = "SELECT `firstname`, `lastname`, `email` FROM `person_list` WHERE `person_list'";
      $result = $conn->query($sql);

      if($result !== false) {
        $html_table = '<table border="1" cellspacing="0" cellpadding="2"><tr><th>First Name</th><th>Last Name</th><th>Email Address</th></tr>';

        foreach($result as $row) {
          $html_table .= '<tr><td>' .$row['firstname']. '</td><td>' .$row['lastname']. '</td><td>' .$row['email']. '</td></tr>';
        }
      }

      $conn = null;

      $html_table .= '</table>';

      echo $html_table;
    }
    catch(PDOException $e) {
      echo $e->getMessage();
    }
    ?>

</html>

Answer 1

In the query: 在查询中：

$sql = "SELECT `firstname`, `lastname`, `email` 
        FROM `person_list` 
        WHERE `person_list'";

You have a quote in person_list' <= which should be a tick ` 您在person_list'有一个引号person_list' <=应该是一个勾号`

Either replace the quote with a tick, or just remove it. 要么将报价单打勾，要么将其删除。

Like this: 像这样：

$sql = "SELECT firstname, lastname, email 
       FROM person_list 
       WHERE person_list";

And add the where condition 并添加where条件

WHERE person_list = value;

Answer 2

1st: your statement is wrong at the where statment 第一：您的陈述在where陈述中是错误的

$sql = "SELECT `firstname`, `lastname`, `email` FROM `person_list` ;";

or 要么

$sql = "SELECT * FROM person_list WHERE (column_name = 'something');";

2nd for seprationg: 分隔第二名：

index.php::: index.php文件:::

<?php require_once("phpcode.php"); ?>
<html>......</html>

phpcode.php phpcode.php

<?php 
................
?>

3rd: displaying- 第三：显示-

<html>...

<table>
<tr>
<th>name</th>
<th>email</th>
</tr>

<?php while ($data=$results->fetch_assoc())
{

print "

 <tr>
 <td>".$data['username']."</td>
 <td>".$data['email']."</td>
 </tr>

";
?>

</table>
....</html>

如何获取mysql数据并以html显示

问题描述

2 个解决方案

解决方案1
3 2015-03-06 13:05:15

解决方案2
1 2015-03-06 13:10:04

如何获取mysql数据并以html显示

问题描述

2 个解决方案

解决方案1 3 2015-03-06 13:05:15

解决方案2 1 2015-03-06 13:10:04

解决方案1
3 2015-03-06 13:05:15

解决方案2
1 2015-03-06 13:10:04