如何在没有排序功能的情况下按字母顺序在python中对文本文件进行排序？

Question

I have to alphabetically sort a text file where each new word is on a new line. I currently have the whitespace stripped and my program prints the first letter attaching it to a integer with the ord function. I cannot use sort and I know I have to put it into a list just not sure how. This is what i wrote for the lists.

lists = [ [] for _ in range( 26 ) ]

Answer 1

If you can't use the sort() method, the sorted() function is your next bet.

words = [...]
sorted_words = sorted(words)

Unlike words.sort() , using sorted() won't modify its input, and it works on arbitrary iterables.

Answer 2

You could use the following function to sort your list of words:

def qsort(array):
    if len(array) < 2:
        return array
    head, *tail = array
    less = qsort([item for item in tail if item < head])
    more = qsort([item for item in tail if item >= head])
    return less + [head] + more

Answer 3

For the range command you have to put two exclusive integers as parameters for example range(0,11) will pick a number between 1 and 10. This is probably why you can use range(). Also you need to use a column to follow range():.