SQL查询以选择年份在两个日期之间的行

Question

Given a Table with from_date date and a to_date date column, I want to select all sets of data where an year, for example 2007, is the year of one of the dates or both or is in between the two dates.

How can i achieve this using mySQL?

Table:

create Table Articleprice
(`ArtikelpreisNR` int, `ArtikelNR` int, `from_Date` date, `to_date` date, `price` int);

Example Testdata

insert into Articleprice
(`ArtikelPreisNR`, `ArtikelNR`,`from_Date`, `to_Date` ,`price`)

values (1, 1, '2006-7-04', '2008-7-04', 10);

SQL: This is returning only the ones, when from_date and to_date = 2007

SELECT
MIN(price)
FROM  Articleprice
WHERE Articleprice.from_Date >= '2007/01/01' and Articleprice.to_Date <= '2007/12/31';

What do I need to do in order to solve my Case?

Answer 1

假设日期实际上是日期而不是字符串，则需要在查询中使用正确的日期格式：YYYY-MM-DD而不是YYY / MM / DD：

WHERE Articleprice.from_Date >= '2007-01-01' and Articleprice.to_Date <= '2007-12-31';

Answer 2

First you build complete dates using the year. For 2007, the dates would be 2007-01-01 and 2007-12-31 (assuming that end dates are inclusive).

Next you use overlapping dates query to find all rows that (i) end inside (ii) start inside (iii) contain or (iv) contained within the year 2007. The query is simply:

SELECT * FROM Articleprice
WHERE '2007-12-31' >= from_Date AND to_date > '2007-01-01'