如何从json_decode出来的数组中获取一个值？

Question

I'm trying to use a few values from this array that comes out of json_decode, but can't get any output from var_dump (which would presumably help me figure out how to access a particular value). I've tried $data[0] also from a suggestion on a similar question.

<?PHP
$json = 'callback({"geobytesinternet":"US","geobytescountry":"United States","geobytesregionlocationcode":"USWI","geobytesregion":"Wisconsin","geobytescode":"WI","geobyteslocationcode":"USWILOLA","geobytescity":"Land O Lakes","geobytescityid":"30028","geobytesfqcn":"Land O Lakes, WI, United States","geobyteslatitude":"46.154598","geobyteslongitude":"-89.396896","geobytescapital":"Washington, DC ","geobytestimezone":"-89.3969","geobytesnationalitysingular":"American","geobytespopulation":"278058881","geobytesnationalityplural":"Americans","geobytesmapreference":"North America ","geobytescurrency":"US Dollar","geobytescurrencycode":"USD","geobytestitle":"The United States"});';

$json = str_replace( 'callback(', '', $json);
$json = str_replace( ');', '', $json);
$json = '[' . $json . ']';

$data = json_decode($json);

echo '<br>decoded: ' . $data;

echo '<br><br>var_dump: ' . var_dump($data[0]);

?>

Answer 1

You are almost there, the function json_decode() takes as input json encoded string. Your string is not properly json encoded, because of this line $json = '[' . $json . ']'; $json = '[' . $json . ']'; .

This is properly encoded json string

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

NULL is returned if the json cannot be decoded or if the encoded data is deeper than the recursion limit. See the documentation .

EDIT: So your code should look something like this:

<?php
$json = 'callback({"geobytesinternet":"US","geobytescountry":"United States","geobytesregionlocationcode":"USWI","geobytesregion":"Wisconsin","geobytescode":"WI","geobyteslocationcode":"USWILOLA","geobytescity":"Land O Lakes","geobytescityid":"30028","geobytesfqcn":"Land O Lakes, WI, United States","geobyteslatitude":"46.154598","geobyteslongitude":"-89.396896","geobytescapital":"Washington, DC ","geobytestimezone":"-89.3969","geobytesnationalitysingular":"American","geobytespopulation":"278058881","geobytesnationalityplural":"Americans","geobytesmapreference":"North America ","geobytescurrency":"US Dollar","geobytescurrencycode":"USD","geobytestitle":"The United States"});';

//Compact a bit the code, note the ');' replacement
//str_replace() can take an array of arguments, so no need to call the function multiple times
$json = str_replace( array('callback(', ');'), '', $json);
//Get elements in a array
$data = json_decode($json);

//See what's inside the array
var_dump($data);

?>

This is a working fiddle.

Answer 2

The decoded data is object array so do something like this:

$result = $data[0];
echo $result->geobytesinternet;