如何在CodeIgniter中使用路由规则获取参数

Question

My base_url is "http://localhost/App-Feeder/"

Default controller is "Detail"

How do i code my routes and controller to get my URL as "http://localhost/App-Feeder/table/place"

Where "place" is a get parameter and should load to another page. i tried like this :

my route.php

$route['table/(:any)'] = "detail/lala/(:any)";

Controller: detail.php

class Detail extends CI_Controller {

    public function lala($place)
    {
        echo "choose=".$place;
    }
}

but it will display :

choose=(:any)

it should be display :

choose=place

Can anyone help me ?

Answer 1

replace

 $route['table/(:any)'] = "detail/lala/(:any)";

with

 $route['table/(:any)'] = "detail/lala/$1";

Answer 2

为了更好地了解codeignitor，请点击此处，并尝试解决您的问题

$route['product/(:any)'] = "catalog/product_lookup_by_id/$1";