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Java中的数字三角形

[英]Numbers triangle in Java

I'm trying to write a program that prints out a triangle made of numbers. 我正在尝试编写一个程序,该程序打印出由数字组成的三角形。 It should look like that: 它看起来应该像这样:

           1
         2 3 4
       3 4 5 6 7
     4 5 6 7 8 9 0
   5 6 7 8 9 0 1 2 3
 6 7 8 9 0 1 2 3 4 5 6    

In my case it returns negative numbers (876543210-1-2-3...) but it should use only 0-9. 就我而言,它返回负数(876543210-1-2-3 ...),但应仅使用0-9。 I could use modulo n%10, but I don't know how to write that. 我可以使用模n%10,但是我不知道该怎么写。 Any help? 有什么帮助吗? Thank you. 谢谢。

import java.util.Scanner ;

public class Triangle {
public static void main (String [] args) {
    Scanner sc = new Scanner(System.in);

    System.out.print("Number: ");
    int n = sc.nextInt();
    int j;
    int i;
    int k = n-1;

    System.out.printf("n=%d\n\n", n);

    for (i=1; i<=(n*2); i=i+2) {
        for (j=0; j<=2*n-1; j++) {
            if (j < k){
                System.out.print(" ");
            }
            else if (j < (k+i)){ 
                    System.out.printf("%d", (n-j));
            }
            else {
                System.out.print(" ");              
            }       
        }
        k = k-1;
    System.out.println();
    }
}
}

This is a possible implementation, I modified your index names because it was a little confusing: 这是一个可能的实现,我修改了您的索引名称,因为这有点令人困惑:

public class Triangle {
    public static void main (String [] args) {
        Scanner sc = new Scanner(System.in);

        System.out.print("Number: ");
        int n = sc.nextInt();

        int startNumber = 1; /* First number in the line */
        int spaces = n - 1;  /* Spaces in the current line */
        int numbers = 1; /* Numbers in the current line */

        System.out.printf("n=%d\n\n", n);


        for (int lineCounter = 0; lineCounter < n; lineCounter++) {
            /* Spaces before the numbers */
            for (int spaceCounter = 0; spaceCounter < spaces; spaceCounter++) {
                System.out.print(" ");
            }
            for (int numberCounter = 0, number = startNumber; numberCounter < numbers; numberCounter++) {
                System.out.printf("%d", (number));
                number = (number + 1) % 10;
            }
            /* Spaces after the numbers */
            for (int spaceCounter = 0; spaceCounter < spaces; spaceCounter++) {
                System.out.print(" ");
            }
            System.out.println();
            startNumber = (startNumber + 1) % 10;
            spaces--;
            numbers += 2;
        }
    }
}

You could create a printTriangle() method like this (explanation follow in the comments): 您可以这样创建一个printTriangle()方法(注释中的解释如下):

static void printTriangle(int numLines) {
    for (int lineNumber = 1; lineNumber <= numLines; lineNumber++) {
        // Print 2 * (numLines - lineNumber) spaces before the first number in the current line
        for (int spacesPerLine = 0; spacesPerLine < 2 * (numLines - lineNumber); spacesPerLine++) {
            System.out.print(" ");
        }
        // First line has 1 number, second has 3, third has 5, etc.
        int numbersPerLine = (2 * lineNumber) - 1;
        // Print the numbers in the current line
        // from lineNumber (inclusive) to lineNumber + numbersPerLine (exclusive)
        for (int number = lineNumber; number < lineNumber + numbersPerLine; number++) {
            System.out.print((number % 10) + " ");
        }
        System.out.println();
    }
}

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