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使用两个相等的值序列化标志枚举

[英]Serialize Flags enum with two equal values

I want to define a flag enum like the following: 我想定义一个如下所示的标志枚举:

[Flags]
[Serializable]
public enum Numbers
{
    [XmlEnum(Name = "One")]
    One = 0x1,
    [XmlEnum(Name = "Two")]
    Two = 0x2,
    [XmlEnum(Name = "Three")]
    Three = 0x4,
    [XmlEnum(Name = "OddNumbers")]
    OddNumbers = One | Three,
    [XmlEnum(Name = "EvenNumbers")]
    EvenNumbers = Two,
    [XmlEnum(Name = "AllNumbers")]
    AllNumbers = One | Two | Three
}

Suppose I create an object which has a Numbers property and I set that property to EvenNumbers . 假设我创建了一个具有Numbers属性的对象,并将该属性设置为EvenNumbers Today, only Two is included in property, but I want to specify EvenNumbers so that if I add Four in the future it will be included in the property as well. 今天,属性中只包含Two ,但是我想指定EvenNumbers这样如果我将来添加Four ,它也将包含在属性中。

However, if I serialize this object using XmlSerializer.Serialize , the XML will say Two because today this is the same underlying value. 但是,如果我使用XmlSerializer.Serialize序列化此对象,XML将说Two因为今天这是相同的基础值。

How can I force the serializer to serialize this property as EvenNumbers ? 如何强制序列化程序将此属性序列化为EvenNumbers

Do something like that: Mark the Number property as XmlIgnore and create another property type of string for return the string value of enum. 做类似的事情:将Number属性标记为XmlIgnore并创建另一个属性类型的string以返回enum的字符串值。

[Serializable]
public class NumberManager
{
    [XmlIgnore]
    public Numbers Numbers { get; set; }

    [XmlAttribute(AttributeName="Numbers")]
    public string NumbersString
    {
        get { return Numbers.ToString(); }
        set { Numbers = (Numbers) Enum.Parse(typeof (Numbers), value); }
    }
}

Then serialize the NumberManager . 然后序列化NumberManager

I hope it helps. 我希望它有所帮助。

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