[英]extract table from html by position using Python
I want to extract a specific table from an html document that contains mutliple tables, but unfortunately there are no identifiers. 我想从包含多张表的html文档中提取特定表,但是不幸的是没有标识符。 There is a table title, however. 但是,有一个表标题。 I just can't seem to figure it out. 我似乎无法弄清楚。
Here is an example html file 这是一个示例html文件
<BODY>
<TABLE>
<TH>
<H3> <BR>TABLE 1 </H3>
</TH>
<TR>
<TD>Data 1 </TD>
<TD>Data 2 </TD>
</TR>
<TR>
<TD>Data 3 </TD>
<TD>Data 4 </TD>
</TR>
<TR>
<TD>Data 5 </TD>
<TD>Data 6 </TD>
</TR>
</TABLE>
<TABLE>
<TH>
<H3> <BR>TABLE 2 </H3>
</TH>
<TR>
<TD>Data 7 </TD>
<TD>Data 8 </TD>
</TR>
<TR>
<TD>Data 9 </TD>
<TD>Data 10 </TD>
</TR>
<TR>
<TD>Data 11 </TD>
<TD>Data 12 </TD>
</TR>
</TABLE>
</BODY>
I can use beautifulSoup 4 to get tables by id or name, but I need just a single table that is only identifiable by position. 我可以使用beautifulSoup 4通过ID或名称获取表,但是我只需要一个只能通过位置识别的表。
I know that I can get the first table with: 我知道我可以通过以下方式获得第一张桌子:
tmp = f.read()
soup = BeautifulSoup(tmp) ## make it readable
table = soup.find('table') ### gets first table
but how would I get the second table? 但是我将如何获得第二张桌子?
You can rely on the table title. 您可以依靠表标题。
Find the element by text passing a function as a text
argument value, then get the parent : 通过传递函数作为text
参数值的text
查找元素,然后获取父对象 :
table_name = "TABLE 1"
table = soup.find(text=lambda x: x and table_name in x).find_parent('table')
If it's only identifiable by position, meaning it's always the 2nd table in the website, you could do: 如果只能通过位置来标识,这意味着它始终是网站中的第二张表,则可以执行以下操作:
tmp = f.read()
soup = BeautifulSoup(tmp)
# this will return the second table from the website
all_tables = soup.find_all('table')
second_table = all_tables[1]
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