在不使用boost :: counting_iterator的情况下插入一系列连续整数的最佳方法

Question

What's the Best way to insert a range of consecutive integers without boost::counting_iterator.[c++]

    // Insert 1 to 9
    set<long> set1.insert(boost::counting_iterator<int>(1)
                          ,boost::counting_iterator<int>(10))

Answer 1

跨范围调用insert for循环工作得很好，并使代码易于维护。

Answer 2

You may use:

std::set<long> s;
long l = 0;
std::generate_n(std::inserter(s, s.end()), 9, [&]{ return ++l; });

or the simple loop:

std::set<long> s;
for (long i = 1; i != 10; ++i) {
    s.insert(i);
}