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在不满足条件的列中显示null

[英]Display null in the column where condition doesn't satisfy

I have two tables 我有两张桌子

TRAINING_EMPLOYEE TRAINING_EMPLOYEE

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TRAINING_DEPARTMENT TRAINING_DEPARTMENT

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From both the tables, i want all the columns except DEPARTMENT_ID from the TRAINING_EMPLOYEE and column DEPARTMENT_NAME from the TRAINING_DEPARTMENT 从两个表中,我都希望除TRAINING_EMPLOYEE中的 DEPARTMENT_ID和TRAINING_DEPARTMENT中的 DEPARTMENT_NAME列之外的所有列

I am doing this 我正在做这个

SELECT TE.EMPLOYEE_ID,TE.FIRST_NAME,TE.LAST_NAME,TO_CHAR(HIRE_DATE ,'DD-
MON-YYYY')HIRE_DATE,TD.DEPARTMENT_NAME FROM training_employee TE,
training_department TD  WHERE TE.DEPARTMENT_ID=TD.DEPARTMENT_ID;

And i am getting this 我正在得到这个 在此处输入图片说明

But i do want all the 4 rows of TRAINING_EMPLOYEE and null on the Department_name if "TRAINING_EMPLOYEE.DEPARTMENT_ID<>TRAINING_DEPARTMENT.DEPARTMENT_ID" 但是,如果“ TRAINING_EMPLOYEE.DEPARTMENT_ID <> TRAINING_DEPARTMENT.DEPARTMENT_ID”,我确实希望所有4行TRAINING_EMPLOYEE都在Department_name上为null

You want a left join . 您想要left join And, it is hard because you are using archaic join syntax that doesn't really support it. 而且,这很困难,因为您使用的是不真正支持它的过时的联接语法。 Here is a simple rule going forward: never use a comma in the from clause. 这是一条简单的规则:不要在from子句中使用逗号。 Always use explicit join syntax: 始终使用显式join语法:

SELECT TE.EMPLOYEE_ID, TE.FIRST_NAME, TE.LAST_NAME,
       TO_CHAR(HIRE_DATE, 'DD-MON-YYYY') as HIRE_DATE, TD.DEPARTMENT_NAME
FROM training_employee TE LEFT JOIN
     training_department TD 
     ON TE.DEPARTMENT_ID = TD.DEPARTMENT_ID;

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