Python-在列表中查找列表得分的平均值

Question

I'm trying to find the average scores of a list in a list, using lambda.

Scores=[['James','Q',3,4,1,5],['Kat','S',3,4,1,2],['John','G',3,5,6,4]['Erikson','G',3,7,6,8],['Filip','NJ',3,8,9,9]]
sortedScores=sorted(Scores,key=lambda score:avg(score[3:],reverse=False))

for i in Scores:
    print(i[0:1],avg(i[3:]))

avg is not a command, so what would be the best way to calculate the average within this code?

Answer 1

You forgot a comma, that's all:

Scores=[
    ['James','Q',3,4,1,5],
    ['Ryan','G',3,4,1,2],
    ['Klodiano','G',3,5,6,4]['Erikson','G',3,7,6,8],
    #                      ^^
    ['Filip','NJ',3,8,9,9]
]

Without the comma, the list ['Klodiano','G',3,5,6,4] is being indexed, but instead of an integer, you passed in the tuple ('Erikson','G',3,7,6,8) .

Note that your sorted() list also has an error:

sortedScores=sorted(
    Scores,
    key=lambda score:avg(score[3:],reverse=False))
    #                ^^^^^^^^^^^^^^^^^^^^^^^^^^^^

You are passing in the reverse=False to the avg() callable, not to sorted() . You probably wanted:

sortedScores=sorted(
    Scores,
    key=lambda score:avg(score[3:]),
    reverse=False)

instead.

You don't need to slice if you wanted to print the name of each student separately; you'd use indexing instead:

for i in Scores:
    print(i[0], avg(i[3:]))

And finally, the GCSE programming problem you are implementing asks for the last 3 scores, not for all scores except the first 1. You need to use -3 to slice of the last 3 scores to calculate the average:

avg(score[-3:])