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在JPA CriteriaQuery中使用@Embeddable实体

[英]Using an @Embeddable entity in a JPA CriteriaQuery

Let's say I have the following example entities - one is an @Embeddable , embedded inside another @Entity : 假设我有以下示例实体 - 一个是@Embeddable ,嵌入在另一个@Entity

@Embeddable
public class ContactInfoEntity {

    @Column
    private String phone;

    @Column
    private String zipCode;
}

@Entity
@Table(name = "EMPLOYEE")
public class EmployeeEntity {

    @Id
    @Column(name = "EMPLOYEE_ID")
    private Long employeeId;

    @Embedded
    @AttributeOverrides({
        @AttributeOverride(name = "phone",
                           column = @Column(name = "EMPLOYEE_PHONE")),
        @AttributeOverride(name = "zipCode",
                           column = @Column(name = "EMPLOYEE_ZIP_CODE"))
    })
    private ContactInfoEntity employeeContactInfo;
}

The meta-model classes generated by the openjpa-maven-plugin include only an employeeContactInfo variable, not the @AttributeOverride columns. openjpa-maven-plugin生成的元模型类仅包含employeeContactInfo变量,而不包括@AttributeOverride列。

Now suppose I want to do this: 现在假设我想这样做:

Select the EMPLOYEE_ID and EMPLOYEE_PHONE where the EMPLOYEE_ZIP_CODE is equal to "123456" 选择EMPLOYEE_IDEMPLOYEE_PHONE ,其中EMPLOYEE_ZIP_CODE等于“123456”

How do I create this as a CriteriaQuery ? 如何将其创建为CriteriaQuery

CriteriaBuilder cb = entityManager.getCriteriaBuilder();

CriteriaQuery<String> qDef = cb.createQuery(String.class);
Root<EmployeeEntity> e = qDef.from(EmployeeEntity.class);
qDef.select(e.get(EmployeeEntity_.employeeId),
            e.get(????))
    .where(cb.equal(e.get(????), "123456"));

return entityManager.createQuery(qDef).getResultList();

An example approach may look like this: 示例方法可能如下所示:

CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Object[]> qDef = cb.createQuery(Object[].class);
Root<EmployeeEntity> e = qDef.from(EmployeeEntity.class);
qDef.multiselect(
     e.get(EmployeeEntity_.employeeId),
     e.get(EmployeeEntity_.employeeContactInfo).get(ContactInfoEntity_.phone));
qDef.where(
     cb.equal(
        e.get(EmployeeEntity_.employeeContactInfo).get(ContactInfoEntity_.zipCode), 
        cb.literal("123456")));

List<Object[]> objects = em.createQuery(qDef).getResultList();
for (Object[] element : objects) {
    System.out.format("%d %s", element[0], element[1]);
}

Depending on your preferences you may also want to get the results of the query as: 根据您的偏好,您可能还希望将查询结果视为:

  • constructor expression 构造函数表达式

     public class EmployeeEntityResult { private int id; private String phone; public EmployeeEntityResult(int id, String phone) { this.id = id; this.phone = phone; } ... } 
     CriteriaQuery<EmployeeEntityResult> cq = cb.createQuery(EmployeeEntityResult.class); ... List<EmployeeEntityResult> result = em.createQuery(cq).getResultList(); for (EmployeeEntityResult element : result) { System.out.format("%d %s", element.getId(), element.getPhone()); } 
  • tuple 元组

     CriteriaQuery<Tuple> cq = cb.createTupleQuery(); ... cq.select( cb.tuple( e.get(EmployeeEntity_.employeeId) .alias("id"), e.get(EmployeeEntity_.employeeContactInfo).get(ContactInfoEntity_.phone) .alias("phone"))); ... List<Tuple> tuple = em.createQuery(cq).getResultList(); for (Tuple element : tuple) { System.out.format("%d %s", element.get("id"), element.get("phone")); } 

The JPQL query looks as follows: JPQL查询如下所示:

SELECT e.id, e.employeeContactInfo.phone
FROM EmployeeEntity e
WHERE e.employeeContactInfo.zipCode = '123456'

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