IOS (Objective-C) 如何从 UIImages 数组无限期更改 UITableView 单元格中的图像

Question

How can I make two images interchangeably animate indefinitely in a UITableViewCell?

Update (Solution so far): I was able to look into UIImage Animations and here's my current solution

NSArray *imagesArray = [NSArray arrayWithObjects:imageA,imageB,nil];
UIImage *x=[UIImage animatedImageWithImages:imagesArray duration:2.0f];
cell.imageView.image=x;

Answer 1

Take a look at the NSTimer class. When you create the timer, you'll specify a target object, a selector, a time interval, and whether or not the timer repeats. Basically, you can have the timer send a message to the view controller in charge of your table every so often. When the view controller receives the message, that method should change the image in the table.

Answer 2

The UIKit has everything ready-made for you.

The UIImageView class has built-in frame based animations. You install an array of images in the image view's animationImages array, configure the timing of the animation, and then start it animating with a startAnimating call. It's well documented in the Xcode docs in the Animating Images section of the UIImageView class reference.

You should create a custom subclass of UITableViewCell that has an image view in it and configure the image view to run a continuously repeating frame animation.

Answer 3

Maybe I am not following what you want to do, but one simple solution would be to just use the properties animationImages and animationDuration on UIImageView in your cell. Have a look at the documentation here: https://developer.apple.com/library/ios/documentation/UIKit/Reference/UIImageView_Class/#//apple_ref/occ/instp/UIImageView/animationImages

You basically just provide an array of images and set the duration to an appropriate length so that each of your images displays for 2/3 of a second as requested.