使用JDT获取内部类方法声明的外部类名称

Question

I can get the class name for each method declaration in Java by using eclipse JDT. So, for a method declared in an inner class, I get the name of the inner class.

Is it possible to get the outer class name for a method declared in an inner class by using JDT.

So far, I'm able to identify whether a class is an inner class or outer class by the following code:

public boolean visit(TypeDeclaration td) {
    className = td.getName().getFullyQualifiedName();
    if (!td.isPackageMemberTypeDeclaration()) 
            System.out.println(className+" is inner class")

    return true;
}

• As I know the inner class name, so is it possible to get it's outer class name by the AST?
• Is there any way to get which .java file the AST parser is processing currently (when a full project is being parsed)?

Answer 1

1. Not sure if this is the ideal way, but you can use the below snippet to get the topmost TypeDeclaration (Outer class).

    public static ASTNode getOuterClass(ASTNode node) { do { node= node.getParent(); } while (node != null && node.getNodeType() != ASTNode.TYPE_DECLARATION && node.isPackageMemberTypeDeclaration()); return node; } 

   Then you can get the class name by:

    ASTNode outerClassNode = getOuterClass(methodDeclarationNode); if (outerClassNode != null) { // not the topmost node System.out.println(outerClassNode.getName()); } 

2. Usually I pass the CompilationUnit as a constructor argument for the ASTVisitor class, and get the file name from same.

UPDATE:

Another way to get the declaring class details:

typDeclarationNode.resolveBinding().getDeclaredTypes();

This will return null, if it is a Top-level class. For inner class, it will return the Outer classes.