Python-删除列表项

Question

Sorry for a lot of questions, that is my code so far, Im not exactly sure how to remove values greater .

compute average of the values in the list and removes all values greater than the average from given list

n = int(input("Number of values in list: "))
numbers = []
average=0
for i in range(n):
    lists = float(input("Enter a floating number: "))
    numbers.append(lists)
    average=average+ lists/n

print (numbers)
if lists>average
value = numbers.pop

thank you :)

Answer 1

response = raw_input('Enter floats separated by spaces')
float_list = map(float, response.split())

Answer 2

b= []
c= [4.5,3.4,3.141592654]
def func(a):
        for numbers in a:
            b.append(numbers)
func(c)

Not sure if that is what you are looking for.

Answer 3

I figured out how to do it using this method, thank you for the help

n = int(input("Number of values in list: "))
numbers = []
average=0
for i in range(n):
    lists = float(input("Enter an float: "))
    numbers.append(lists)
    average=average+ lists/n
print(numbers)

Answer 4

for my understanding, you just want a list of numbers, then remove all the numbers which bigger than the average? you can just filter the numbers not bigger than average.

n = int(input("Number of values in list: "))
numbers = []
average=0
for i in range(n):
    lists = float(input("Enter a floating number: "))
    numbers.append(lists)
    average=average+ lists/n

print (numbers)

# filter numbers not greater than average, and get a new list
numbers = [n for n in numbers if n <= average]
print (numbers)