[英]How to add and update the objects of two dimensional array in objective-c?
I want to make a two dimensional array in objective-c and initialize all the indexes as zero. 我想在Objective-C中创建一个二维数组,并将所有索引初始化为零。 whenever my data (2D Coordinate) matches with any row/column then I want to upgrade the respective index by value one. 每当我的数据(2D坐标)与任何行/列匹配时,我都希望通过值1升级相应的索引。 So that later on I can scan for my highly probable coordinate on the basis of maximum number of index at any point. 这样一来,以后我就可以在任意点基于最大索引数扫描我的高度可能坐标。 For eg: If my algorithm generates coordinate (0,1), then the index at first row and second column must increase by one. 例如:如果我的算法生成坐标(0,1),则第一行和第二列的索引必须增加一个。 Thanks a lot. 非常感谢。
Here is how you create your array. 这是创建数组的方式。
NSMutableArray *array = [[NSMutableArray alloc] init];
[array addObject:[NSMutableArray arrayWithObjects:@"0",@"0",nil]];
[array addObject:[NSMutableArray arrayWithObjects:@"0",@"0",nil]];
NSLog(@"%@",array);
Update value 更新值
Say you want to update index(0,1)
with value 3
, you do 假设您要用值3
更新index(0,1)
,您可以
[[array objectAtIndex:0] replaceObjectAtIndex:1 withObject:@"3"];
NSLog(@"%@",array);
Update index(1,1)
with value 4
do 用值4
更新index(1,1)
[[array objectAtIndex:1] replaceObjectAtIndex:1 withObject:@"4"];
NSLog(@"%@",array);
Hope it helps. 希望能帮助到你。
Cheers. 干杯。
如果需要,可以使用数字并使用简单的方法来编写数组:
NSMutableArray * array2d = @[@[@0,@0], @[@0,@1]];
Just a suggestion: 只是一个建议:
Objective-C is a super set of C. So you can make use of the C array concept also. Objective-C是C的超集。因此,您也可以使用C数组的概念。
int array2D[5][5] = {0};//The compiler will automatically intialize all indces to 0.
or use 或使用
memset(&a[0][0], 0, sizeof(int) * 5 * 5);
then use the simple C assignment like as follows, 然后使用如下所示的简单C赋值,
array2D[0][1] = 3;
which is much faster and simple. 更快,更简单。
#include<stdio.h>
#include<string.h>
int main(int argc, char * argv[])
{
int a[5][5];
memset(&a[0][0], 0, sizeof(int) * 5 * 5);
for(int i = 0; i < 5; i++)
{
for(int j = 0; j < 5; j++)
{
printf("%d ", a[i][j]);
}
printf("\n");
}
return 0;
}
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